Eksponentna enačba in logaritem; nova osnova

$$x=\frac{\log3}{\log2}$$

$$x=\log_32$$

$$x=\frac{\ln3}{\ln2}$$

$$x=\log_23$$

$$x=\frac{\log2}{\log3}$$

$$x=\frac{\log25}{\log\ \frac{1}{5}}$$

x = - 2

$$x=\frac{\log\ \frac{1}{5}}{\log25}$$

$$x=\log_{\frac{1}{5}}25$$

$$x=\frac{\log\ \frac{6}{5}}{\log12}$$

$$x=\frac{\log30}{\log36}$$

$$x=\frac{\log6+\log5}{2\log6}$$

Pravilo količnika

Prehod k novi osnovi logaritma

Logaritem produkta

Logaritem potence

2 in 3

1 in 2

-1 in 0

3 in 4

1 in 2

2 in 3

-1 in 0

0 in 1

$$\frac{\log200}{\log9}$$

$$\frac{\ln200}{\ln9}$$

$$\frac{\log_N200}{\log_N9}$$

$$\frac{\ln9}{\ln200}$$

$$\log_{27}x$$

$$\frac{3\log_3x}{2}$$

$$3\log_3x$$

$$\frac{\log_3x}{2}$$

$$\frac{\log_5x}{\log_{25}x}$$

$$2\log_5x$$

$$\frac{\log_5x}{2}$$

$$\log_{\ \frac{1}{5}}x$$