Solve Systems of Equations by Substitution

Solve for x and y by using the substitution method.

y = 2x + 1

y = 4x - 1

• (1, 3)

• (-1, -3)

• (-1, 3)

• (3, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y by using the substitution method.

3x + 2y = 16

y = -7x + 19

• (-2, 5)

• (-2, -5)

• (2, -5)

• (2, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by using the substitution method.

x = 3y + 1

2x + 4y = 12

• (4, 1)

• (1, 4)

• (3, 1)

• (1, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y using the substitution method.

5x + 3y = 7

y = 4

• (4, 1)

• (4, -1)

• (1, 4)

• (-1, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system?

8x + 4y = 12
y = -2x + 3

• (0, 3)

• (3, 0)

• No solution (parallel lines)

• Infinitely many solutions

Tags

CCSS.8.EE.C.8B

What is the solution?

• 1

• -2

• (1, 2)

• (1, -1)

Tags

CCSS.8.EE.C.8B

What is the solution to the system?

y = 2x +4

2x - y = -6

• No solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system?

• No solution

• (0, 3)

• (0, -2)

• (2, 4)

Tags

CCSS.8.EE.C.8A

How many solutions will this system have?

• No solution

• Infinitely many solutions

• (1, 0)

• One solution

Tags

CCSS.8.EE.C.8B

The solution to a system of equations is any ordered pair that makes both equations true. 

• True

• False

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6