Balancing Redox Reactions in Acidic Solution

Balancing Redox Reactions in Acidic Solution

11th Grade

15 Qs

quiz-placeholder

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Balancing Redox Reactions in Acidic Solution

Balancing Redox Reactions in Acidic Solution

Assessment

Quiz

Chemistry

11th Grade

Hard

Created by

Saurabh Deshwar

Used 3+ times

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of oxygen in H2O2?

-1

2

4

0

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Balance the following redox reaction in acidic solution: MnO4- + H2O2 -> Mn2+ + O2

2MnO4- + 4H2O2 -> 2Mn2+ + 4O2 + 4H2O

2MnO4- + 6H2O2 -> 2Mn2+ + 3O2 + 4H2O

MnO4- + 2H2O2 -> Mn2+ + O2 + 2H2O

2MnO4- + 6H2O2 -> 2Mn2+ + 5O2 + 8H2O

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the half-reaction for the reduction of MnO4- to Mn2+ in acidic solution?

MnO4- + 6H+ + 5e- -> Mn2+ + 3H2O

MnO4- + 8H+ + 5e- -> Mn2+ + 4H2O

MnO4- + 4H+ + 3e- -> Mn2+ + 2H2O

MnO4- + 2H+ + 3e- -> Mn2+ + H2O

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Balance the following redox reaction in acidic solution: Cl2 + NO3- -> Cl- + NO

Cl2 + 2NO3- -> 2Cl- + 2NO

2Cl2 + 10NO3- + 12H+ -> 2Cl- + 10NO + 6H2O

2Cl2 + 10NO3- + 12H+ -> 2Cl- + 10NO + 6H2O + 2H+

2Cl2 + 10NO3- + 6H+ -> 2Cl- + 10NO + 3H2O

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the half-reaction for the oxidation of Cl2 to Cl- in acidic solution?

2Cl2 -> 4Cl-

2Cl2 + 2e- -> 4Cl-

2Cl2 + 2e- -> 2Cl-

Cl2 + 2e- -> 2Cl-

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Balance the following redox reaction in acidic solution: Cr2O7^2- + Fe2+ -> Cr3+ + Fe3+

14H+ + Cr2O7^2- + 6Fe2+ -> 2Cr3+ + 6Fe3+ + 3H2O

14H+ + Cr2O7^2- + 6Fe2+ -> 2Cr3+ + 6Fe3+ + 8H2O

14H+ + Cr2O7^2- + 6Fe2+ -> 2Cr3+ + 6Fe3+ + 5H2O

14H+ + Cr2O7^2- + 6Fe2+ -> 2Cr3+ + 6Fe3+ + 7H2O

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the half-reaction for the reduction of Cr2O7^2- to Cr3+ in acidic solution?

2Cr2O7^2- + 14H+ + 8e- -> 2Cr3+ + 7H2O

2Cr2O7^2- + 10H+ + 6e- -> 2Cr3+ + 5H2O

2Cr2O7^2- + 14H+ + 4e- -> 2Cr3+ + 7H2O

2Cr2O7^2- + 14H+ + 6e- -> 2Cr3+ + 7H2O

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