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Features of Quadratics Review

Authored by Erin Ondrusek

Mathematics

11th Grade

CCSS covered

Used 9+ times

Features of Quadratics Review
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10 questions

Show all answers

1.

LABELING QUESTION

45 sec • 1 pt

Label the key features of the quadratic

e
f
d

range

x-intercept

line of symmetry

domain

vertex

y-intercept

Tags

CCSS.HSF-IF.C.7A

2.

CATEGORIZE QUESTION

45 sec • 1 pt

Drag the functions into the correct column: does the parabola open upward or downward?

Groups:

(a) Upward

,

(b) Downward

f(x)=−4x2−3x+5f\left(x\right)=-4x^2-3x+5  

f(x)=−2(x+7)(x−1)f\left(x\right)=-2\left(x+7\right)\left(x-1\right)  

f(x)=3(x−2)2+1f\left(x\right)=3\left(x-2\right)^2+1  

f(x)=−23(x+2)2f\left(x\right)=-\frac{2}{3}\left(x+2\right)^2  

f(x)=12x2−7f\left(x\right)=\frac{1}{2}x^2-7  

f(x)=(x−4)(x+10)f\left(x\right)=\left(x-4\right)\left(x+10\right)  

f(x)=−(x+8)2+3f\left(x\right)=-\left(x+8\right)^2+3  

Tags

CCSS.HSF-IF.C.7A

3.

GRAPHING QUESTION

2 mins • 1 pt

Graph the quadratic: y=14x2−1x−3y=\frac{1}{4}x^2−1x−3

Tags

CCSS.HSF-IF.C.7A

4.

MATCH QUESTION

1 min • 1 pt

Match the equation with its vertex.

(−4,−3)\left(-4,-3\right)

y=12(x+4)2−3y=\frac{1}{2}\left(x+4\right)^2-3

(5, 2)\left(5,\ 2\right)

y=−(x+3)2−4y=-\left(x+3\right)^2-4

(−2, 5)\left(-2,\ 5\right)

y=−23(x−5)2+2y=-\frac{2}{3}\left(x-5\right)^2+2

(4, −3)\left(4,\ -3\right)

y=2(x−4)2−3y=2\left(x-4\right)^2-3

(−3, −4)\left(-3,\ -4\right)

y=3(x+2)2+5y=3\left(x+2\right)^2+5

5.

MATH RESPONSE QUESTION

2 mins • 1 pt

Write the equation of a quadratic equation that goes through (0, 3), (4, −1) & (9, 84)\left(0,\ 3\right),\ \left(4,\ -1\right)\ \&\ \left(9,\ 84\right)

y=2x2−9x+3y=2x^2-9x+3

Mathematical Equivalence

ON

6.

MATCH QUESTION

1 min • 1 pt

Match the quadratic function with its intercepts.

(1, 0) & (−7, 0)\left(1,\ 0\right)\ \&\ \left(-7,\ 0\right)

f(x)=−(x−5)(x−3)f\left(x\right)=-\left(x-5\right)\left(x-3\right)

(5, 0) & (−3, 0)\left(5,\ 0\right)\ \&\ \left(-3,\ 0\right)

y=(x−1)(x+7)y=\left(x-1\right)\left(x+7\right)

(−1, 0) & (7, 0)\left(-1,\ 0\right)\ \&\ \left(7,\ 0\right)

f(x)=13(x+5)(x+3)f\left(x\right)=\frac{1}{3}\left(x+5\right)\left(x+3\right)

(−5, 0) & (−3, 0)\left(-5,\ 0\right)\ \&\ \left(-3,\ 0\right)

f(x)=2(x+1)(x−7)f\left(x\right)=2\left(x+1\right)\left(x-7\right)

(5, 0) & (3, 0)\left(5,\ 0\right)\ \&\ \left(3,\ 0\right)

f(x)=−3(x−5)(x+3)f\left(x\right)=-3\left(x-5\right)\left(x+3\right)

Tags

CCSS.HSA.APR.B.3

7.

MATCH QUESTION

1 min • 1 pt

The equation h(t)=−16t2+96t+20h\left(t\right)=-16t^2+96t+20 represents the height of a ball launched off a platform. Interpret the y-intercept, x-intercept and vertex. (Match)

The ball hits the ground in 6.2 seconds.

x-intercept

The ball is launched from 20 feet

y-intercept

Reaches a max of 164 feet in 3 seconds.

vertex

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