Quiz about Unit 3 Lesson 16

Question 1

After writing step 1 in your notes, what are a, b, & c in the given equation.

Accepted Answer

a=1b=-6c=7

Answer

a=0b=-6c=7

Answer

a=1b=6c=7

Answer

a=0b=6c=7

Question 2

After writing step 2 AND the formula in your notes, answer the given question.

What do you think the next step will be?

Accepted Answer

Substitute a, b, and c into the equation.

Answer

Simplify the radical.

Answer

Simplify the fracton.

Answer

There is not a next step. The answer is complete.

Question 3

What does x equal?

Accepted Answer

10, -10

Answer

10

Answer

10i, -10i

Answer

-10

Question 4

What does x equal?

Accepted Answer

$$\sqrt[]{38},\ -\sqrt[]{38}$$

Answer

38, -38

Answer

no solution

Answer

19

Question 5

What does x equal? (Hint: Use the quadratic formula. Make sure to check your answers!)

Accepted Answer

5

Answer

-5

Answer

5, -5

Answer

$$\sqrt[]{5}$$

Question 6

What does x equal?

Accepted Answer

-10, -4

Answer

10, 4

Answer

-10i, -4i

Answer

10i, 4i

Question 7

What does x equal? Fully simplify both fractions.

Accepted Answer

$$-7+\frac{\sqrt[]{40}}{2}$$

$$-7-\frac{\sqrt[]{40}}{2}$$

Answer

$$-\frac{14}{2}+\frac{\sqrt[]{40}}{2}$$

$$-\frac{14}{2}-\frac{\sqrt[]{40}}{2}$$

Answer

$$-14+\sqrt[]{40}$$

$$-14-\sqrt[]{40}$$

Answer

$$-7+\frac{i\ \sqrt[]{40}}{2}$$

$$-7-\frac{i\ \sqrt[]{40}}{2}$$

Question 8

What does x equal? Fully simplify both fractions.

Accepted Answer

$$\frac{5}{6}+\frac{\sqrt[]{157}}{6}$$

Answer

$$5+\sqrt[]{157}$$

$$5-\sqrt[]{157}$$

Answer

$$\frac{5}{2}+\frac{\sqrt[]{157}}{2}$$

Answer

$$\frac{5}{6}+\frac{i\ \sqrt[]{157}}{6}$$

Question 9

What is the Quadratic Formula?

Accepted Answer

$$\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$

Answer

$$\frac{b\pm\sqrt[]{b^2-4ac}}{2a}$$

Answer

$$\frac{-b\pm\sqrt[]{b-4ac}}{2a}$$

Answer

$$\frac{-b\pm\sqrt[]{b^2-4ac}}{2}$$

Question 10

What does x equal?

Accepted Answer

-2

Answer

-2, 2

Answer

2i, -2i

Answer

2

Question 11

What does x equal? Fully simplify.

Accepted Answer

$$\frac{7}{10}+\frac{\sqrt[]{89}}{10}$$

$$\frac{7}{10}-\frac{\sqrt[]{89}}{10}$$

Answer

$$-\frac{7}{10}+\frac{\sqrt[]{89}}{10}$$

$$-\frac{7}{10}-\frac{\sqrt[]{89}}{10}$$

Answer

$$7+\sqrt[]{89}$$

$$7-\sqrt[]{89}$$

Answer

$$\frac{7}{10}+\frac{i\ \sqrt[]{89}}{10}$$

$$\frac{7}{10}-\frac{i\ \sqrt[]{89}}{10}$$

Unit 3 Lesson 16

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