Control Systems Quiz

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The Bode plot of a transfer function G(s) is shown in the figure below. The gain (20log|G(s)|) is 32 dB and -8dB at 1 rad/s and 10 rad/s respectively. The phase is negative for all w. Then G(s) is

• 39.8/s

• 39.8/s²

• 32/s

• 32/s²

Assuming zero initial condition, the response y(t) of the system given below to a unit step input u(t) is

• u(t)

• tu(t)

• t²u(t)/2

• e^-tu(t)

The signal flow graph for a system is given below. The transfer function Y(s)/U(s) for this system is

• s+1/5s²+6s+2

• s+1/s²+6s+2

• s+1/s²+4s+2

• 1/5s²+6s+2

The open-loop transfer function of a dc motor is given as ω(s)/V_a(s)=10/(1+10s). When connected in feedback as shown below, the approximate value of K_a that will reduce the time constant of the closed loop system by one hundred times as compared to that of the open-loop system is

• 1

• 5

• 10

• 100

The transfer function of a compensator is given as fig.

G_c(s) is a lead compensator if

• a=1,b=2

• a=3,b=2

• a=-3,b=-1

• a=3,b=1

The phase of the above lead compensator is maximum at

• √2 rad/s

• √3 rad/s

• √6 rad/s

• 1/√3 rad/s

The frequency response of a linear system G(jω) is provided in the tubular form below

• 6 dB and 30°

• 6 dB and -30°

• -6dB and 30°

• -6dB and -30°

The steady state error of a unity feedback linear system for a unit step input is 0.1. The steady state error of the same system, for a pulse input r(t) having a magnitude of 10 and a duration of one second, as shown in the figure is

• 0

• 0.1

• 1

• 10