Semester Review

Factor
k²+7x+10

• (k+2)(k+5)
• (k-2)(k-5)
• (k+10)(k+4)
• (k+2)(k-5)

Factor x² - 25

• ( x + 5 ) ( x - 5 )

• ( x - 5 ) ( x - 5 )

• ( x + 5 ) ( x + 5 )

• Prime

Factor completely:

x² + 9x - 36

• (x + 12)(x - 3)

• (x + 9)(x - 4)

• (x - 12)(x + 3)

• (x - 9)(x - 4)

Factor completely:

5n³-10n²+3n-6

• (5n²+3)(n-2)

• (5n²-3)(n-2)

• (5n³+3)(n-2)

• 10n(n²-6)

Factor completely:

x³ + 2x² - 49x - 98 

• (x² - 49) (x + 2) 

• (x² - 49) (x + 2) (x + 2) 

• (x + 7) (x - 7) (x + 2) 

Factor this difference of cubes:
x³ - 343

• (x + 7) (x² - 7x + 49)
• (x² + 1) (x - 343)
• (x - 7) (x² + 7x + 49)
• (x² - 343) (x + 1)

x³ -512

• ( x - 8) ( x + 200)

• ( x + 8) ( x + 20)

• (x+8)(x²-8x+64)

• (x-8)(x²+8x+64)

Solve for X:

(x-5)(x+6)=0

• {5,5 }

• { -5,-5 }

• { -5,-6 }

• {5,-6 }

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3