Math Antics Division Quiz
5th Grade
•15 Qs
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Math Antics Division Quiz
Quiz
•
Mathematics
•
5th Grade
•
Practice Problem
•
Medium
+1
Standards-aligned
Jamison W
Used 4+ times
FREE Resource
Enhance your content in a minute
15 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of 16 divided by 5?
3 with a remainder of 1
3 with a remainder of 2
4 with a remainder of 1
4 with a remainder of 2
Tags
CCSS.4.NBT.B.6
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the standard division algorithm for 16 divided by 5?
Model the problem with a drawing
Use the Method of Partial Quotients
Set up the problem and go digit-by-digit
Use decimals to divide up remainders
Tags
CCSS.3.OA.C.7
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is one advantage of the Method of Partial Quotients?
It is only suitable for division problems with small divisors
It always results in fewer steps than the standard method
It allows for flexibility in choosing multiples for each step
It requires memorization of many multiplication facts
Tags
CCSS.5.NBT.B.6
CCSS.6.NS.B.2
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final answer for 6428 divided by 35 using the Partial Quotients Method?
183 r 23
180 r 28
185 r 18
190 r 15
Tags
CCSS.5.NBT.B.6
CCSS.6.NS.B.2
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the advantage of using the Partial Quotients Method for division problems with large divisors?
It is only suitable for division problems with small divisors
It allows for flexibility in choosing multiples for each step
It requires memorization of specific multiplication facts for each divisor
It always results in fewer steps than the standard method
Tags
CCSS.5.NBT.B.6
CCSS.6.NS.B.2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of 1276 divided by 26?
47 with a remainder of 4
49 with a remainder of 2
50 with a remainder of 1
48 with a remainder of 3
Tags
CCSS.5.NBT.B.6
CCSS.6.NS.B.2
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main advantage of the Partial Quotients Method?
It is only suitable for division problems with small divisors
It always results in fewer steps than the standard method
It allows for flexibility in choosing multiples for each step
It requires memorization of specific multiplication facts for each divisor
Tags
CCSS.5.NBT.B.6
CCSS.6.NS.B.2
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