高次不等式與三次函數複習

(1,-3)

(-1,-3)

(1,3)

(-1,3)

$$y=x^3$$

$$y=x^3+3x^2$$

$$y=x^3+3x^2+5x$$

$$y=x^3+3x^2+5x+6$$

y=6(x-3)+14

y=6x+14

y=5x-7

y=3x+14

$$y=5x+6$$

$$y=2x+5$$

$$y=14x+1$$

$$y=6$$

(2,4]

[2,4)

(2,4)

[2,4]

(2,4]

[2,4)

(2,4)

[2,4]

$$\left(\infty,2\right)\cap\left(4,\infty\right)$$

$$\left(\infty,2\right)\cup\left(4,\infty\right)$$

$$\left(\infty,2\right]\cap\left[4,\infty\right)$$

$$\left(\infty,2\right]\cup\left[4,\infty\right)$$

$$\left(-\infty,1\right]\cup\left[3,4\right]\cup\left[6,\infty\right)$$

$$\left(-\infty,1\right)\cup\left(3,4\right)\cup\left(6,\infty\right)$$

$$\left(-\infty,1\right]\cap\left[3,4\right]\cap\left[6,\infty\right)$$

$$\left(-\infty,1\right)\cap\left(3,4\right)\cap\left(6,\infty\right)$$

$$3\cup6$$

$$3$$

$$3\cap6$$

$$6$$

$$\left(6,\infty\right)$$

$$\left[6,\infty\right)$$

$$\left(6,\infty\right]$$

$$\left[6,\infty\right]$$