
Sample
Quiz
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Education
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Professional Development
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Practice Problem
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Hard
Walid Badr
Used 2+ times
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37 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A major brokerage house is currently selling an investment product that offers an 8% rate of return, compounded monthly. Based on this information, it follows that this investment has:
Answer explanation
Periodic rate = 8.0 / 12 = 0.667. Stated rate is 8.0% and effective rate is 8.30%. (Study Session 1, Module 1.1, LOS 1.c)
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A stated interest rate of 9% compounded quarterly results in an effective annual rate closest to:
Answer explanation
Quarterly rate = 0.09 / 4 = 0.0225. Effective annual rate = (1 + 0.0225)4 – 1 = 0.09308, or 9.308%.(Study Session 1, Module 1.1, LOS 1.c)
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Peter Wallace wants to deposit $10,000 in a bank certificate of deposit (CD). Wallace is considering the following banks: Bank A offers 5.85% annual interest compounded annually. Bank B offers 5.75% annual interest rate compounded monthly. Bank C offers 5.70% annual interest compounded daily. Which bank offers the highest effective interest rate and how much?
Answer explanation
Effective interest rates: Bank A = 5.85 (already annual compounding) Bank B, nominal = 5.75; C/Y = 12; effective = 5.90 Bank C, nominal = 5.70, C/Y = 365; effective = 5.87 Hence Bank B has the highest effective interest rate. (Study Session 1, Module 1.1, LOS 1.c)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Nikki Ali and Donald Ankard borrowed $15,000 to help finance their wedding and reception. The annual payment loan carries a term of seven years and an 11% interest rate. Respectively, the amount of the first payment that is interest and the amount of the second payment that is principal are approximately:
Answer explanation
Step 1: Calculate the annual payment. Using a financial calculator (remember to clear your registers): PV = 15,000; FV = 0; I/Y = 11; N = 7; PMT = $3,183 Step 2: Calculate the portion of the first payment that is interest. Interest1 = Principal × Interest rate = (15,000 × 0.11) = 1,650 Step 3: Calculate the portion of the second payment that is principal. Principal1 = Payment – Interest1 = 3,183 – 1,650 = 1,533 (interest calculation is from Step 2) Interest2 = Principal remaining × Interest rate = [(15,000 – 1.533) × 0.11] = 1,481 Principal2 = Payment – Interest1 = 3,183 – 1,481 = 1,702 (Study Session 1, Module 1.3, LOS 1.f)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Fifty years ago, an investor bought a share of stock for $10. If the stock has experienced 2% compound annual growth over the period, its price today is closest to:
Answer explanation
10(1.02)50 = $26.91 Alternatively, N = 50; I/Y = 2; PV = –10; PMT = 0; CPT → FV = $26.91 (Study Session 1, Module 1.2, LOS 1.e)
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Sarah Parker is buying a new $25,000 car. Her trade-in is worth $5,000 so she needs to borrow $20,000. The loan will be paid in 48 monthly installments and the annual interest rate on the loan is 7.5%. If the first payment is due at the end of the first month, what is Sarah's monthly car payment?
Answer explanation
N = 48; I/Y = 7.5 / 12 = 0.625; PV = 20,000; FV = 0; CPT → PMT = 483.58 (Study Session 1, Module 1.3, LOS 1.f)
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Justin Banks just won the lottery and is trying to decide between the annual cash flow payment option or the lump sum option. He can earn 8% at the bank and the annual cash flow option is $100,000/year, beginning today for 15 years. What is the annual cash flow option worth to Banks today?
Answer explanation
First put your calculator in the BGN. N = 15; I/Y = 8; PMT = 100,000; CPT → PV = 924,423.70. Alternatively, do not set your calculator to BGN, simply multiply the ordinary annuity (end of the period payments) answer by 1 + I/Y. You get the annuity due answer and you don't run the risk of forgetting to reset your calculator back to the end of the period setting. OR N = 14; I/Y = 8; PMT = 100,000; CPT → PV = 824,423.70 + 100,000 = 924,423.70. (Study Session 1, Module 1.2, LOS 1.e)
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