Math 20-2 Quiz

What is the vertex form of a quadratic function?

• y = a(x + h)^2

• y = a(x + h)^2 - k

• y = a(x - h)^2 + k

• y = a(x - h) + k

What is the quadratic formula and how is it used to solve quadratic equations?

• The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a) and it is used to solve cubic equations.

• The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a) and it is used to solve quadratic equations.

• The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a) and it is used to solve exponential equations.

• The quadratic formula is x = (b ± √(b^2 - 4ac)) / (2a) and it is used to solve linear equations.

Solve the quadratic equation x^2 - 6x + 8 = 0 using the quadratic formula.

• x = 4 or x = 2

• x = 1 or x = 8

• x = 10 or x = -2

• x = 3 or x = 5

Factor the quadratic equation 2x^2 + 7x + 3 = 0 to find its roots.

• (2x + 1)(x + 3)

• (2x - 1)(x - 3)

• (2x + 3)(x + 1)

• (2x - 3)(x - 1)

Find the vertex of the parabola y = 3x^2 - 12x + 5 using the vertex formula.

• The vertex is (3, -2)

• The vertex is (0, 5)

• The vertex is (5, 12)

• The vertex is (2, -7)

How do you create a quadratic equation given the vertex and a point on the parabola?

• Use the quadratic formula and substitute the given point to solve for 'a'.

• Use the vertex form of a quadratic equation and substitute the given point to solve for 'a'.

• Use the standard form of a quadratic equation and substitute the given point to solve for 'a'.

• Use the slope-intercept form of a quadratic equation and substitute the given point to solve for 'a'.

Create a quadratic equation with the vertex (2, -3) and the point (4, 5).

• y = 2(x - 2)^2 + 3

• y = 2(x - 2)^2 - 3

• y = -2(x - 2)^2 - 3

• y = 2(x + 2)^2 - 3