Seminar 2

What is the MIPS assembly equivalent for the C declaration char greeting[6] = {'H', 'e', 'l', 'l', 'o', '\0'};?

• greeting: .asciiz "Hello"

• greeting: .char 'H','e','l','l','o',0

• greeting : .byte ’H’,’e’,’l’,’l’,’o’,’\0’

• greeting: .space 6

What is the MIPS assembly equivalent for the C declaration char my_string[] = "I’m the string?

• str: .asciiz "I’m the string"

• str: .word 'I','’','m',' ','t','h','e',' ','s','t','r','i','n','g',0

• str: .byte "I’m the string"

• str: .space 14

What is the MIPS assembly equivalent for the C declaration int vector_1 [10];?

• vector_1 : .data 10

• vector_1 : .space 40

• vector_1 : .word 10

• int vector_1 [10];

What is the purpose of the following MIPS assembly instructions?

• Compute the product of $t3 and $t4, storing the result in $t5.

• Multiply the values in $t3 and $t4 and store the lower 32 bits of the result in $t5

• Add the values in $t3 and $t4 and store the result in $t5

• Divide the values in $t3 and $t4, storing the quotient in $t5

What is the purpose of the following MIPS assembly instructions?

• Divide the values in $t5 and $t4, storing the quotient in $t6 and the remainder in $t2.

• Multiply the values in $t5 and $t4, storing the lower 32 bits of the result in $t6 and the upper 32 bits in $t2.

• Divide the values in $t4 and $t5, storing the quotient in $t6 and the remainder in $t2.

• Multiply the values in $t4 and $t5, storing the lower 32 bits of the result in $t6 and the upper 32 bits in $t2.

Make 0x2 ⊕ 0x5 (where ⊕ stands for exclusive-or)

• 0111

• 0110

• 0100

• 0000

Indicate what will be the hexadecimal value of the bytes stored in the memory addresses (hexadecimal) 0x10010004?

• @0x10010004: 0x09

• @0x10010004: 0x-7

• @0x10010004: 0xF9

• @0x10010004: 0x02

What happens after executing the following codes?

• The code loads a halfword from the memory address A+7 into register $t1 without any issues.

• The expression A+7 results in accessing the 7th element of the array

• The expression A+7 results in a value that is not multiple of 2, error when loading the half

• The code will always execute without errors.

What happens after executing the following codes?

• This loads the byte in memory address A+1

• Raise an error as address is not multiple of 4

• Raise an error because trying to load the zero address

• Nothing happens

How was the seminar?

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