Kuis Persamaan Lingkaran

$$1$$

$$\sqrt[]{5}$$

$$5$$

$$25$$

$$625$$

$$x^2+y^2=11$$

$$x^2+y^2=22$$

$$x^2+y^2=111$$

$$x^2+y^2=121$$

$$x^2+y^2=131$$

$$x^2+y^2=6$$

$$x^2+y^2=8$$

$$x^2+y^2=16$$

$$x^2+y^2=20$$

$$x^2+y^2=32$$

$$x^2+y^2=4$$

$$x^2+y^2=8$$

$$x^2+y^2=16$$

$$x^2+y^2=32$$

$$x^2+y^2=64$$

$$12\pi$$

$$14\pi$$

$$16\pi$$

$$140\pi$$

$$144\pi$$

$$\left(x+1\right)^2+\left(y-2\right)^2=25$$

$$\left(x-1\right)^2+\left(y+2\right)^2=25$$

$$\left(x+1\right)^2+\left(y-2\right)^2=5$$

$$\left(x-1\right)^2+\left(y+2\right)^2=5$$

$$\left(x-1\right)^2+\left(y-2\right)^2=25$$

$$9$$

$$10$$

$$11$$

$$12$$

$$13$$

$$\left(1,\ 5\right)$$

$$\left(1,\ -5\right)$$

$$\left(-1,\ 5\right)$$

$$\left(5,\ -1\right)$$

$$\left(-5,\ 1\right)$$

$$\left(x+5\right)^2+\left(y+2\right)^2=16$$

$$\left(x-5\right)^2+\left(y-3\right)^2=20$$

$$\left(x-4\right)^2+\left(y-3\right)^2=25$$

$$\left(x+4\right)^2+\left(y+3\right)^2=25$$

$$\left(x-4\right)^2+\left(y+8\right)^2=36$$

$$\left(1,\ -2\right)$$

$$\left(2,\ -4\right)$$

$$\left(4,\ -8\right)$$

$$\left(-1,\ 2\right)$$

$$\left(-2,\ 4\right)$$