
Alg. 2 - 5.4 Synthetic Division and Zeros
Quiz
•
Mathematics
•
University
•
Medium
+2
Standards-aligned
Amy McNabb
Used 4+ times
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13 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
True or False?
Since 2 + 3i is a zero of
f(x) = x2 - 4x + 13,
then 2 - 3i is also a zero.
True
False
2.
FILL IN THE BLANK QUESTION
1 min • 1 pt
Given that 4 - 6i is a zero of f(x), what is another zero of f(x)?
Answer explanation
Remember that non-real complex zeros come in pairs. Both conjugates are zeros.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Cam divided (x4 + 3x2 - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?
Cam wrote the remainder incorrectly.
Cam did not use a zero place holder for the x3 term.
Cam added instead of subtracting the rows.
Cam should have used -2 as his division since the factor was x-2.
Tags
CCSS.HSA.APR.D.6
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Use synthetic division: (2x3 - 5x - 7) ÷ (x - 2)
Answer explanation
When you set it up, don't forget to put in your placeholder since you skip the x^2 term:
(2x3 + 0x^2 - 5x - 7) ÷ (x - 2)
2 0 -5 -7 as your coefficients
with 2 on the outside.
Tags
CCSS.HSA.APR.D.6
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Use synthetic division: if 𝒙2+𝟑𝒙+𝟕 is divided by 𝒙+𝟐, then what is the remainder?
Answer explanation
Remember to put -2 on the outside since it makes your x + 2 that you're dividing by = 0.
Tags
CCSS.HSA.APR.D.6
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Find all the x-intercepts of the function
f(x) = 2x3 - 19x2 + 38x + 24 given that (x-4) is a factor.
x = 1/2, -6
x = -1/2, 6
x = 4, -1/2, 6
x = -4, 1/2, -6
Answer explanation
f(x) = 2x3 - 19x2 + 38x + 24 given that (x-4) is a factor.
Divide by x-4. You should get 2x^2 - 11x + 6 and then can that.
Tags
CCSS.HSF-IF.C.7C
7.
MULTIPLE SELECT QUESTION
45 sec • 1 pt
Find all the other factors of x3 -3x2 -4x +12 given that x+2 is a factor..
(x-2)
(x+5)
(x+3)
(x-3)
Answer explanation
Divide by x+2, and you should get x^2 - 5x + 6. Then factor your result.
Tags
CCSS.HSA.APR.B.2
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