If given the equation y = 3(x + 5)² - 4, what is the vertex of the parabola?

• (5, -4)
• (-5, -4)
• (-15, -4)
• (15, -4)

What is the vertex of the parabola: y=2(x-3)²+4

• (3,4)
• (-3,4)
• (3, -4)
• (-3,-4)

Write an equation of the parabola with the given characteristics:

Focus: (3, 5)

Vertex: (3, -1)

If a parabola has a focus at (0,3) and a vertex at the origin...what is the equation of the directrix?

• y=3

• y=-3

• x=3

• x=-3

• (−2,2)

• (−2,4)

• (−6,2)

• (−5,2)

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Tags

TEKS.MATH.P.3G

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Tags

TEKS.MATH.P.3G

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p = __

(__, __)