Quadratic Functions Graphing Skills

Graph the quadratic function y = 2x^2 - 4x + 1 in standard form.

• Graph the parabola with vertex at (0, 1) and opening downwards.

• Graph the parabola with vertex at (2, 1) and opening upwards.

• Graph the line y = 2x - 4.

• Graph the parabola with vertex at (1, -3) and opening upwards.

Solve the system of equations by graphing: y = x^2 - 4x + 3 and y = 2x - 1.

• Graphing is not a valid method for solving systems of equations

• The answer is 42

• This is a free response question and the answer will vary based on the specific points of intersection found on the graph.

• The solution is y = x^2 - 4x + 3 + 2x - 1

Graph the quadratic function y = (x-3)^2 - 4 in vertex form.

• The vertex is at (0, 4)

• The graph is a parabola that opens downwards

• The graph of the quadratic function y = (x-3)^2 - 4 in vertex form is a parabola that opens upwards with the vertex at (3, -4).

• The graph is a straight line with a negative slope

Graph the quadratic function y = (x-2)(x+3) in factored form.

• Plot the y-intercept and connect the points to form the graph

• Graph the quadratic function y = (x-2)(x+3) in factored form by finding the x-intercepts and plotting the points on the graph.

• Use the quadratic formula to solve for x

• Graph the linear function y = 2x + 3 instead

Apply the transformation y = -2(x-1)^2 + 3 to the graph of y = x^2.

• The graph of y = -2(x-1)^2 - 3 is a parabola that opens upwards

• The graph of y = -2(x-1)^2 + 3 is a parabola that opens downwards, shifted 1 unit to the right, and 3 units up from the graph of y = x^2.

• The graph of y = -2(x-1)^2 + 3 is a hyperbola

• The graph of y = -2(x+1)^2 + 3 is a straight line

Graph the quadratic function y = -x^2 + 4x - 5 in standard form.

• Option A: Graph the parabola with vertex at (2, -9) and opening downwards.

• Option A: Graph the parabola with vertex at (0, -5) and opening upwards.

• Option B: Graph the line with y-intercept at (0, -5) and slope of 4.

• Option C: Graph the parabola with vertex at (4, -5) and opening upwards.

Solve the system of equations by graphing: y = x^2 - 2x - 3 and y = 3x - 1.

• The point of intersection is (2, 5).

• The point of intersection is (3, 7)

• The point of intersection is (0, -3)

• The point of intersection is (1, 2)

Graph the quadratic function y = (x+2)^2 - 1 in vertex form.

• y = (x+2)^2 - 1

• y = (x-2)^2 + 1

• y = (x+1)^2 - 2

• y = x^2 - 4x + 3

Graph the quadratic function y = (x-1)(x-4) in factored form.

• Graph the parabola with x-intercepts at (2,0) and (3,0), and note that it opens downwards.

• Graph the parabola with x-intercepts at (-1,0) and (-4,0), and note that it opens upwards.

• Graph the linear function y = x - 5.

• Graph the parabola with x-intercepts at (1,0) and (4,0), and note that it opens upwards.

Apply the transformation y = 0.5(x+1)^2 - 2 to the graph of y = x^2.

• y = 0.5(x+1)^2 + 2

• y = 0.5(x+2)^2 - 2

• y = 0.5(x-1)^2 - 2

• y = 0.5(x-2)^2 - 2