Substitution Review

The first step in solving using the substitution method is __________.

• get x by itself
• get y by itself
• get either variable by itself
• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:
x = -1
y = 3x + 2

• (1, 1)
• (2, -1)
• (-1, -1)
• (-1, 2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Use the system of equations below to answer the question.

After substituting the first equation into the second one and working it out, I got x = 1. What should I do next?

y = 6x

2x + 5y = 32

• Fill in 1 for x in y = 6x

• Fill in 1 for y in y = 6x

• Fill in 1 for y in 2x + 5y = 32

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following systems of equations using substitution:

x = 6

y = 2x - 3

• (6, 6)

• (6, 9)

• (9, 6)

• (9, 9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by using the Substitution Method.

(Pay attention to which variable is easiest to use for substitution.)

2x + 3y = 14

x = -4y + 2

• (-3, 0)

• (8, 2)

• (-3, -1)

• (10, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system of equations. 
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using the substitution method. (Remember, this one is a little different. You basically make them equal to each other.)

y = 8x + 1

y = 6x + 3

• (1, 9)

• (4, 14)

• (0, 1)

• (2, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Tags

CCSS.7.EE.B.4A