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Concentration Pre-Quiz Review

Authored by Lauren Morriss

Chemistry

11th Grade

Used 2+ times

Concentration Pre-Quiz Review
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15 questions

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1.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

How many L are required to make 3.5 M hydrochloric acid using 1.1 moles? 

3.18 L

0.31 L

3.85 L

4.6 L

Answer explanation

To make 3.5 M HCl with 1.1 moles, divide moles by molarity: 1.1 moles / 3.5 M = 0.31 L

2.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

If you have 0.045 L of 0.465 M potassium bromide. How many moles of potassium bromide are present?

20.9 mol

0.021 mol

0.02 mol

0.0209 mol

Answer explanation

To find the moles of potassium bromide, multiply the volume (0.045 L) by the molarity (0.465 M) to get 0.0209 mol.

3.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?

0.018 M

0.0011 M

1.052 M

0.062 M

Answer explanation

To find the molarity, first calculate the moles of NaCl: 4g / 58.45 g/mol = 0.0684 mol. Then, convert mL to L: 3800 mL = 3.8 L. Finally, divide moles by liters: 0.0684 mol / 3.8 L = 0.018 M.

4.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Find the molarity of 186.55 g of sucrose, C12H22O11 (MM = 342) in 250 mL of water.

2.18 M

0.746 M

1.18 M

0.545 M

Answer explanation

Calculate moles of sucrose, then divide by volume in liters to get molarity: (186.55 g / 342 g/mol) / (250 mL / 1000 mL/L) = 2.18 M

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?

2.0 M

0.22 m

135 m

2.0m

Answer explanation

The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, 3.0 moles of NaCl in 1.5 kg of water gives a molality of 2.0m.

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the molality of a solution made by dissolving 2 moles of NaOH in 400 grams of water?

5 mol/kg. solvent

4 mol/kg solvent

3 mol/kg. solvent

2.5 moles /kg solvent

Answer explanation

The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, 2 moles of NaOH in 400g of water gives a molality of 5 mol/kg solvent.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many kilograms of H2O must be added to 75.5 g of Ca(NO3)2 to form a 0.500m solution?

0.920 Kg

0.00662 Kg

37.75 Kg

0,03775 Kg

Answer explanation

To calculate the amount of H2O needed, use the formula: moles of Ca(NO3)2 = moles of H2O. Convert 75.5g Ca(NO3)2 to moles, then to kg to find 0.920 Kg of H2O.

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