Chemical Equilibrium Quiz

What is the state of a chemical reaction at equilibrium?

• The concentrations of all reactants and products remain constant with time.

• The concentrations of all reactants and products steadily increase.

• The reaction stops completely.

• The concentrations of products decrease while reactants increase.

What does the equilibrium position lying to the right indicate?

• The reaction favors the reactants.

• The reaction is not at equilibrium.

• The reaction favors the products.

• The reaction rate of the forward reaction is slower than the reverse reaction.

What is the equilibrium constant expression for the reaction jA + kB ⇌ lC + mD?

• Kc = [A]^j[B]^k / [C]^l[D]^m

• Kc = [C]^l[D]^m / [A]^j[B]^k

• Kc = [A]^l[B]^m / [C]^j[D]^k

• Kc = [C]^j[D]^k / [A]^l[B]^m

What must you remember when calculating the equilibrium constant (K)?

• K is calculated using initial concentrations.

• K is calculated using the coefficients as exponents.

• K is dimensionless.

• K is calculated using the products over reactants.

If the balanced equation for a reaction is multiplied by a factor X, how does the new K value relate to the old K value?

• The new K value is the old K value raised to the power of X.

• The new K value is the old K value divided by X.

• The new K value is the old K value multiplied by X.

• The new K value is the reciprocal of the old K value.

What remains the same for a certain reaction at a specific temperature, regardless of the initial concentrations of the reactants and products?

• The equilibrium position

• The rate of the forward reaction

• The value of K

• The rate of the reverse reaction

How can Kc be calculated for the reverse reaction, given the Kc for the forward reaction?

• By taking the square of the original equilibrium constant

• By taking the reciprocal of the original equilibrium constant

• By raising the original equilibrium constant to the second power

• By dividing the original equilibrium constant by two

What is the value of Kc for the reaction 2HI(g) ⇌ H2(g) + I2(g) given [HI] = 0.777M, [H2] = 0.233M, and [I2] = 0.233M at equilibrium?

• 0.12

• 0.014

• 8.3

• 1.0

If the Kc for the reaction 4HI(g) ⇌ 2H2(g) + 2I2(g) is obtained by raising the old Kc to the second power, what would be the new Kc given the old Kc was 0.12?

• 0.0144

• 0.24

• 0.012

• 0.014

What is the relationship between Kp and Kc?

• Kp = Kc + (RT)Δn

• Kp = Kc(RT)Δn

• Kp = Kc / (RT)Δn

• Kp = Kc - (RT)Δn