3/14 Conditional Probability Quiz

3/14 Conditional Probability Quiz

10th Grade

7 Qs

quiz-placeholder

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3/14 Conditional Probability Quiz

3/14 Conditional Probability Quiz

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
HSS.CP.A.4, HSS.CP.B.7, HSS.CP.A.5

+1

Standards-aligned

Created by

Kimberly Villanueva

Used 2+ times

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability that a female is chose given they like a Toyota? 

.525
.4627
.6774
.3143

Tags

CCSS.HSS.CP.A.4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

P(Pizza|Senior):

12/15

4/5
2/3
10/5

Tags

CCSS.HSS.CP.A.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A bag contains 8 blue marbles, 7 green marbles, and 5 yellow marbles. Suppose you drew one marble from the bag above, replaced it and then drew a second marble. What is the probability of picking a non-green marble on both draws? P(not green, not green)

9/16

1/2

9/25

169/400

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

In a standard deck of 52 cards there are 13 diamonds and 13 hearts (red) and 13 spades and 13 clubs (black).  Find the probability of choosing a card at random that is a spade OR a 7

Addition Rule: P(A) + P(B) - P(A and B) = P(A or B)

1/52
1/13
4/13
17/52

Tags

CCSS.HSS.CP.B.7

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the probability of choosing a student at random that plays an instrument OR a team sport

Addition Rule: P(A) + P(B) - P(A and B) = P(A or B)

1/2
13/20
21/20
4/5

Tags

CCSS.HSS.CP.B.7

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Is the event INDEPENDENT or DEPENDENT?
You have a jar with 24 pieces of chocolate candy and 14 pieces of orange candy.  We take one piece of candy at random from the jar, put it back, and then take a second piece of candy at random from the jar.

Independent
Dependent

Tags

CCSS.HSS.CP.A.5

7.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Choose the THREE formulas or statements that show that events A and B are

independent.

P(A and B) = P(A) P(B)

P(A or B) = P(A) + P(B) - P(A and B)

P(A) is the same whether event B happens or not.

P(A | B) = P(A)

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

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