Writing Exponential Functions

A new savings account is opened with $400 and gains 3% every year. What is the exponential function?

• f(x)=400(.97)^x
• f(x)=400(1-0.03)^x
• f(x)=400(1.03)^x
• f(x)=400(0.03)^x

Tags

CCSS.HSF.LE.A.2

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation?

• y=8(15,000)^x
• y=15,000(1.08)^x
• y=15,000(0.92)^x
• y=15,000(0.08)^x

Tags

CCSS.HSF.LE.A.2

Write an exponential function to model the situation. Then solve.

The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year. What will the cost be after 4 years?

• C(t) = 12000(1.06)^t ; $3149.72

• C(t) = 12000(.06)^t ; $3149.72

• C(t) = 12000(.06)^t ; $1472.95

• C(t) = 12000(1.06)^t ; $15149.72

Tags

CCSS.HSF.LE.A.2

The amount of cola in a soda machine decreases by a rate of 5% each hour. The amount of cola in the machine was originally 75 gallons.

Which function models the amount of cola in gallons after h hours?

• f(h) = 75(-5)^h

• f(h) = -5(75)^h

• f(h) = .95(75)^h

• f(h) = 75(0.95)^h

Tags

CCSS.HSF.LE.A.2

Write an exponential function to model the situation. You invest $1500. Your investment increases at a rate of 3.5%.

• B(t) = 1500(0.965)^t

• B(t) = 1500(1.035)^t

• B(t) = 1500(.035)^t

• B(t) = 1500(1.965)^t

Tags

CCSS.HSF.LE.A.2

Write an exponential function to model the situation. The value of a car is $18000 and is depreciating at a rate of 12% per year.

• V(t) = .88(18000)^t

• V(t) = .12(18000)^t

• V(t) = 18000(.88)^t

• V(t) = 18000(.12)^t

Tags

CCSS.HSF.LE.A.2

What is the decay rate for the function: f(x) = 800(0.85)^x?

• 800

• 0.85

• 15%

• x

Tags

CCSS.HSF-IF.C.8B

The equation f(x) = 300(1.06)^x is being used to calculate the amount of money in a savings account.  What does the 1.06 represent?

• 6% growth
• 6% decay
• 1.06% growth
• .06% decay

Tags

CCSS.HSF-IF.C.8B

Write an exponential function to model the situation. Then solve.

The value of a car is $18000 and is depreciating at a rate of 12% per year. What will the value of the car be after 10 years?

• V(t) = 18000(.88)^t ; $12986.98

• V(t) = 18000(.12)^t ; $12986.98

• V(t) = 18000(.88)^t ; $5013.02

• V(t) = 18000(.12)^t ; $5013.02

Tags

CCSS.HSF.LE.A.2

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the decay factor?

• ^0.08

• ^1.08

• 0.92

• 8

Tags

CCSS.HSF-IF.C.8B