DIVISION STANDARDIZED ASSESSMENT (MATHEMATICS 10)

What do you call the arrangement of objects in which order is important?

• A. Factorial

• B. Probability

• C. Permutation

• D. Combination

Which is true about combination?

• A. sequence of objects

• B. same as permutation

• C. order is not important

• D. arrangement of objects matters

The probability of heads landing up when you flip a coin is 1/2. What is the probability of getting tails if you flip it again?

• A. 1/4

• B. 1/3

• C. 1/2

• D. 3/4

Which of the following methods rearranges objects by means of showing them systematically through a diagram?

• A. Tree Diagram

• B. Listing Method

• C. Tabular Method

• D. Graphical Method

It consists of all outcomes that are both in events A and B, denoted by A Ո B.

• A. Compound events

• B. Intersection of events

• C. Simple events

• D. Union of events

If a set contains all the elements that are in both events A or B, then it likely implies that:

• A. Event A is dependent to event B.

• B. There is union between events A and B.

• C. Events A and B are independent to each other.

• D. An intersection takes place between A and B.

It refers to the set of all possible outcomes of a probability experiment.

• A. Event

• B. Outcomes

• C. Probability

• D. Sample space

If an event is in set R but not in set S, which of the following statements is TRUE?

• A. The event is in the union of R and S.

• B. The event is not in the union of R and S.

• C. The event is in the intersection of R and S.

• D. The event is in both the union and intersection of R and S.

The different ways in which the letters R, S, T can be grouped together taken all at a time are RST, RTS, STR, TSR, TRS, SRT. Which method of arrangement is illustrated?

• A. Tree Diagram

• B. Listing Method

• C. Tabular Method

• D. Graphical Method

When there are no common outcomes in P(A) and P(B), which equation will determine the P(A ∪ B)?

• A. P(A ∪ B) = P(A) – P(B)

• B. P(A ∪ B) = P(A) + P(B)

• C. P(A ∪ B) = P(A) – P(B) + P(A ∩ B)

• D. P(A ∪ B) = P(A) + P(B) – P(A ∩ B)