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Tes 4

Authored by anzo rudhe_alias_M_Teguh_Rudiansyah

Mathematics

12th Grade

Used 1+ times

Tes 4
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18 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Untuk a = 4 dan b = 8, nilai (a2b−132a−12b)−1= ....\left(\frac{a^2b^{-\frac{1}{3}}}{2a^{-\frac{1}{2}}b}\right)^{-1}=\ ....

-2

-1

−12-\frac{1}{2}

1

2

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Bentuk sederhana dari 4(2+3)(2−3)3+5\frac{4\left(2+\sqrt[]{3}\right)\left(2-\sqrt[]{3}\right)}{3+\sqrt[]{5}} adalah ...

−12(3−5)-\frac{1}{2}\left(3-\sqrt[]{5}\right)

−14(3−5)-\frac{1}{4}\left(3-\sqrt[]{5}\right)

14(3−5)\frac{1}{4}\left(3-\sqrt[]{5}\right)

12(3−5)\frac{1}{2}\left(3-\sqrt[]{5}\right)

(3−5)\left(3-\sqrt[]{5}\right)

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari 3log⁡82−3log⁡12523log⁡100(3log⁡5−3log⁡2)=...\frac{^3\log_8^2-^3\log_{125}^2}{^3\log_{100}^{ }\left(^3\log_5-^3\log_2\right)}=...

−35-\frac{3}{5}

−910-\frac{9}{10}

−32-\frac{3}{2}

−3-3

−92-\frac{9}{2}

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan Kuadrat −2x2+3x−2=0-2x^2+3x-2=0 memiliki akar-akar x1 dan x2x_1\ dan\ x_2 , nilai x13+x23=x_1^3+x_2^3=

98\frac{9}{8}

38\frac{3}{8}

−18-\frac{1}{8}

−38-\frac{3}{8}

−98-\frac{9}{8}

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

nilai m yang mungkin agar persamaan kuadrat 4x2−4m2x−3m+2=04x^2-4m\sqrt[]{2}x-3m+2=0 mempunyai akar-akar kembar adalah ...

{12,−2}\left\{\frac{1}{2},-2\right\}

{12,2}\left\{\frac{1}{2},2\right\}

{−12,−2}\left\{-\frac{1}{2},-2\right\}

{−12,2}\left\{-\frac{1}{2},2\right\}

{−12}\left\{-\frac{1}{2}\right\}

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Pak Ali bekerja selama 6 hari dengan 4 hari di antaranya lembur mendapat upah Rp74.000,00. Pak Bisri bekerja selama 5 hari dengan 2 hari di antaranya lembur mendapat upah Rp55.000,00. Pak Ali, Pak Bisri, dan Pak Catur bekerja dengan aturan upah yang sama. Jika Pak catur bekerja 4 hari dengan terus menerus lembur, maka upa yang diperoleh adalah ...

Rp36.000,00

Rp46.000,00

Rp56.000,00

Rp60.000,00

Rp70.000,00

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Lingkaran x2+y2−16x−12y=0x^2+y^2-16x-12y=0 memotong sumbu Y di titik P. Salah satu persamaan garis singgung lingkaran di titik P adalah ...

y=43x+12y=\frac{4}{3}x+12

y=−43x+12y=-\frac{4}{3}x+12

y=34x+9y=\frac{3}{4}x+9

y=34x+12y=\frac{3}{4}x+12

y=−34x+12y=-\frac{3}{4}x+12

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