
AP Physics 2 Ultimate Review
Authored by KELLY DOYLE
Physics
11th Grade
NGSS covered
Used 10+ times

AI Actions
Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...
Content View
Student View
84 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Container A has a sample of gas A, while container B has a sample of gas B. The atoms of both gases currently have the same average speed, but the molecules of gas B have a greater molar mass than the molecules of gas A. What can be concluded about the temperatures?
Gas A & gas B are the same temperature
Gas A has a greater temperature
Gas B has a greater temperature
Cannot be determined without knowing the number of molecules in each container
Answer explanation
Temperature is directly proportional to kinetic energy.
K = (3/2) kBT
Whichever gas has more kinetic energy will have a greater temperature.
K = 0.5mv2
The speeds (v) is the same, but gas B has a greater mass, so it will have more kinetic energy and therefore a greater temperature.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Two capacitors are wired in series as shown. The circuit has reached steady state. A student measures the charge on the 4 μF and finds it a non-zero +Q0.
How does Kirchhoff's loop rule apply to this circuit?
It doesn't, it only applies to circuits with batteries
The two capacitors will have potential differences equal in magnitude
The voltage drop across the 2 μF will be twice that of the voltage drop across the 4 μF
There is a voltage drop in the wire itself equal to the voltage drop in the capacitors
Capacitors do not have voltage drops across them
Answer explanation
Kirchhoff's law applies to all circuits, whether or not they have a battery.
In in this loop, the potential differences must add up to zero. The trick here is that each capacitor will have the same magnitude of voltage drop, but in opposite directions.
At steady state, the wire will have no significant voltage drop, even if it did have some natural resistance. This is because there is no significant current flow in the wire at steady state.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Two capacitors are wired in series as shown. The circuit has reached steady state. A student measures the charge on the 4 μF and finds it a non-zero +Q0.
What is the magnitude of charge on the 2 μF capacitor?
0.5Q0
Q0
2Q0
4Q0
0
Answer explanation
Due to Kirchhoff's loop rule, these two capacitors have equal and opposite voltage drops.
V4 = V2
(Q0 / C4) = (Q2 / C2)
(Q0 / 4 μF) = (Q2 / 2 μF)
Q0 = 2Q2
Q2 = 0.5Q0
Another way to think of it. The 2 μF capacitor has half the "room" for electrons as compared to the 4 μF. That is essentially what capacitance is: it's a reflection on the capacitor's ability to hold electrons.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A convex mirror has a focal located 0.3 m behind it. If you place an object 0.5 m in front of the mirror, where is the image formed?
0.2 in front of the mirror
0.32 m in front of the mirror
0.19 m behind the mirror
0.45 behind the mirror
Answer explanation
For convex mirrors, the focal is located BEHIND the mirror, where light rays cannot actually go. For this reason, the focal in convex mirrors must be NEGATIVE when doing the math.
(1 / 0.5) + (1 / si) = (1 / −0.3)
(1 / si) = −0.5333
si = −0.1875 m
The si is negative, which tells us this image forms behind the mirror.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The current through resistor X is measured to be 4 A and the current through resistor Y is 1 A. What is the current through resistor Z?
4 A
3 A
1 A
Cannot be determined without knowing more values
Answer explanation
The junction law says that the total current going into a junction is the amount of current coming out of the junction.
There are 4 amps before the junction. Then, one of the branches has 1 amp. So, the other branch must have 3 amps!
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A, B, C, and D represent processes by which an electron drops to a lower orbit. Which process will result in the greatest frequency of photon emitted?
A
B
D
They all emit the same frequency
Answer explanation
The larger the energy drop, the greater the energy of photon released. Process D has the electron falling from E = -2 eV to E = -10 eV. This is a change of energy of -8 eV, meaning the photon released has 8 eV of energy.
Energy is directly proportional to frequency for photons (E = hf). More energy means more frequency.
Tags
NGSS.HS-PS4-3
7.
FILL IN THE BLANK QUESTION
1 min • 1 pt
A chef grabs a hot pan and burns his hand. By what primary process did the heat transfer into his hand?
Access all questions and much more by creating a free account
Create resources
Host any resource
Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever
or continue with

Microsoft
%20(1).png)
Apple
Others
Already have an account?
Similar Resources on Wayground
81 questions
Electricity & Circuits Review
Quiz
•
9th - 12th Grade
86 questions
HPHS T1 Physics Midterm Review
Quiz
•
11th Grade
80 questions
Simulasi Olimpiade Sains Kebumian
Quiz
•
10th - 12th Grade
84 questions
VẬT LÝ 11-HK2-2023-2024
Quiz
•
11th Grade
85 questions
Ôn tập Vật Lý 11
Quiz
•
11th Grade
80 questions
Đề cuong Lý giữa kỳ 1-HK1
Quiz
•
11th Grade
83 questions
Sử ck2
Quiz
•
11th Grade
80 questions
Révisions Seconde maths-sciences
Quiz
•
1st - 12th Grade
Popular Resources on Wayground
15 questions
Fractions on a Number Line
Quiz
•
3rd Grade
20 questions
Equivalent Fractions
Quiz
•
3rd Grade
25 questions
Multiplication Facts
Quiz
•
5th Grade
54 questions
Analyzing Line Graphs & Tables
Quiz
•
4th Grade
22 questions
fractions
Quiz
•
3rd Grade
20 questions
Main Idea and Details
Quiz
•
5th Grade
20 questions
Context Clues
Quiz
•
6th Grade
15 questions
Equivalent Fractions
Quiz
•
4th Grade