Mini-Quiz 6-7: Inverse Relations & Functions

$$t$$ is not a function; the inverse of $$t$$ is a function

$$t$$ is a function; the inverse of $$t$$ is not a function

Both $$t$$ and the inverse of $$t$$ are functions

Neither $$t$$ nor the inverse of $$t$$ are functions

$$y=\frac{x}{2}-4$$

$$y=\frac{2-x}{8}$$

$$y=\frac{8-x}{2}$$

$$x=2x+8$$

$$g^{-1}\left(x\right)=\left(6-x\right)^{4\ }$$

$$g^{-1}\left(x\right)=-\frac{1}{4}x+\frac{3}{2}$$

$$g^{-1}\left(x\right)=-\frac{1}{6}x+\frac{2}{3}$$

$$g^{-1}\left(x\right)=\frac{1}{4}x+\frac{3}{2}$$

No; each $$x$$ in the domain does not map to only one $$y$$ in the range.

Yes; for each $$x$$ in the domain of $$g^{-1}$$ , there is only one value of $$y$$ in the range.

Does not exist

does not exist

0