Balloon Stoichiometry Lab QUIZ

Which balloon/test tube combination of the following will produce the most CO2?

• Balloon 1 (0.2 g of Sodium bicarbonate) with Test Tube 1 (10 mL of acetic vinegar)

• Balloon 2 (0.4 g of Sodium bicarbonate) with Test Tube 2 (10 mL of acetic vinegar)

• Balloon 3 (0.6 g of Sodium bicarbonate) with Test Tube 3 (10 mL of acetic vinegar)

• None of the combinations

What gas inflated the balloons?

• Helium

• Carbon dioxide

• Nitrogen

• Oxygen

How does the mass of a reactant affect the amount of gas produced during a chemical reaction?

• The mass of the reactant does not affect the amount of gas produced.

• Greater mass of a reactant produces more gas.

• Less mass of a reactant produces more gas.

• The effect varies depending on other factors.

Using the balanced equation CH₃COOH + NaHCO₃ --> CH₃COONa + CO₂ + H₂O

If you had 10 mL of vinegar, which has a mass of 10.5 g, what is the theoretical amount of baking soda that would be needed to react? (apply Stoichiometry calculations).

Help: Molar mass of sodium bicarbonate is 84.01 g/mole and molar mass of vinegar is 60.05 g/mole

• 0.2 grams

• 1.0 gram

• 10.0 grams

• 14.0 grams

Find the expression you would use to find the number of moles of baking soda (NaHCO3) in a sample of 0.2 g. The molar mass of baking soda in 84.01 g/mole

• 0.2 g x (1 mol/84.01 g)

• 0.2 g x (84.01 g/1 mol)

• 0.2 g x (6.023x10^23 molecules/1 mole)

• 0.2 g x (1 mole/6.023x10^23 molecules)

The mass of 10 mL of vinegar is 10.5 g. Knowing that the density of vinegar is 1.05 g/mL, choose what expression below will give you that mass.

• 10 mL x (1.05 g / 1 mL)

• 10 mL x (1 mL/1.05g)

• 1.05 mL x (10.00 g / 1 mL)

• 10 g x (1.05 mL / 1 g)

If in the sample with 0.2 g of Baking soda, there are 0.0024 mole of baking soda, what expression you would use to find the number of molecules of baking soda in that sample?

• 0.2 g x (6.023x10^23 molecules / 1 mole)

• 0.0024 mole x (6.023x10^23 molecules / 1 mole)

• 0.0024 g x (6.023x10^23 molecules / 1 mole)

• 0.2 mole x (6.023x10^23 molecules / 1 mole)

If in the sample of 0.2 g of baking soda, there are 1.43 x 10^21 molecules of baking soda, how many molecules of baking soda would it be in the sample with 1.0 g of baking soda?

Help: Molar mass of baking soda is 84.01 g/mole and Avogadro's number is 60.23 x 10^23 molecules / 1 mole

• The same amount

• The double of the amount

• 2.32 x 10^22 molecules

• 7.2 x 10^21 molecules