number of moles

number of moles

9th - 12th Grade

12 Qs

quiz-placeholder

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number of moles

number of moles

Assessment

Quiz

Chemistry

9th - 12th Grade

Medium

Created by

Sahar Fawal

Used 5+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The number 6.02 x 1023 is called...
Obama's number
Bohr's number
Trump's number
Avogadro's number

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Molar mass is in units of ________.

grams

grams/mole

mole

moles/gram

Answer explanation

Molar mass is defined as the mass of one mole of a substance, which is expressed in grams per mole (g/mol). Therefore, the correct answer is grams/mole.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the mass of 2.50 mole of oxygen gas O2?
M(O)= 16g/mol

40 g

80 g

16 g

32 g

Answer explanation

The molar mass of O2 is 32 g/mol. For 2.50 moles, the mass is 2.50 moles × 32 g/mol = 80 g. Therefore, the correct answer is 80 g.

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

How many moles are present in 32.3 grams of carbon dioxide (CO2)?

M(C)=12 g/mol ; M(O)=16 g/mol

44.01 moles

1421.52 moles

32.3 moles

0.73 moles

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

How many potatoes are in one dozen potatoes?

10

12

2

6.02 x 1023

Answer explanation

A dozen refers to a quantity of 12. Therefore, in one dozen potatoes, there are 12 potatoes. The correct answer is 12.

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the molar mass of C2H4O2?

M(C)= 12 g/mol ; M(H)=1g/mol ; M(O)=16g/mol

40g

50g

60g

68g

Answer explanation

To find the molar mass of C2H4O2, calculate: (2x12) + (4x1) + (2x16) = 24 + 4 + 32 = 60g. Thus, the correct answer is 60g.

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If I need 20.4 moles of sodium chloride, how much should I weigh out?

M(Na)= 23g/mol ; M(Cl)= 35.5 g/mol

0.549 g

112 g

1193 g

5077 g

Answer explanation

To find the mass of sodium chloride needed, use the formula: mass = moles × molar mass. The molar mass of NaCl is approximately 58.44 g/mol. Thus, 20.4 moles × 58.44 g/mol = 1192 g, making 1192 g the correct answer.

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