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Unit 2 Test Correction

Authored by Keonna Cole

Mathematics

11th Grade

CCSS covered

Used 1+ times

Unit 2 Test Correction
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16 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Given: 3^x = 30. Which of the following expressions is the value of x?

log_3 30

log 30 / 3

sqrt(30)

30 / 3

Tags

CCSS.HSF.BF.B.5

2.

OPEN ENDED QUESTION

15 mins • 1 pt

Enter the value of x in the equation log_3(6x - 3) = 2.

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OFF

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which of these is equivalent to the value of log base 2 of 5?

log base 5 of 2

log 10

log 32

log base 5 of 5 over log base 2 of 5

4.

OPEN ENDED QUESTION

15 mins • 1 pt

A Petri dish starts off with 5 bacteria. The number of bacteria grows at a rate of 3.5% per minute. How many minutes will it take the Petri dish to have 10 bacteria? Round to the nearest minute.

Evaluate responses using AI:

OFF

Tags

CCSS.HSF.LE.A.4

5.

FILL IN THE BLANK QUESTION

15 mins • 1 pt

Media Image

The organizers of a single-elimination tennis tournament created a table that relates the number of matches played in the tournament, x, and the number of rounds in the tournament, y. Enter a logarithmic expression that is equivalent to y in the box below.

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which of the following functions BEST represents positive exponential growth?

f(x) = 6 * (8/7)^x

f(x) = 4 * (3/4)^x

f(x) = -5 * (1/3)^x

f(x) = -3/2 * 5^x

Tags

CCSS.HSF-IF.C.8B

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A scientist is studying how bacteria thrive under different conditions of temperature and pressure. The scientist develops bacteria population models for the different conditions, as shown below. The models predict the bacteria population, P, after t hours. - Condition 1: P(t) = 500(0.3)^t - Condition 2: P(t) = 500(1.65)^t - Condition 3: P(t) = 500(0.95)^t - Condition 4: P(t) = 500(0.2)^t Which condition models an exponential growth of the bacteria population over time?

P(t) = 500(0.3)^t

P(t) = 500(1.65)^t

P(t) = 500(0.95)^t

P(t) = 500(0.2)^t

Tags

CCSS.HSF.LE.A.2

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