
Unit 2 Test Correction
Authored by Keonna Cole
Mathematics
11th Grade
CCSS covered
Used 1+ times

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16 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Given: 3^x = 30. Which of the following expressions is the value of x?
log_3 30
log 30 / 3
sqrt(30)
30 / 3
Tags
CCSS.HSF.BF.B.5
2.
OPEN ENDED QUESTION
15 mins • 1 pt
Enter the value of x in the equation log_3(6x - 3) = 2.
Evaluate responses using AI:
OFF
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Which of these is equivalent to the value of log base 2 of 5?
log base 5 of 2
log 10
log 32
log base 5 of 5 over log base 2 of 5
4.
OPEN ENDED QUESTION
15 mins • 1 pt
A Petri dish starts off with 5 bacteria. The number of bacteria grows at a rate of 3.5% per minute. How many minutes will it take the Petri dish to have 10 bacteria? Round to the nearest minute.
Evaluate responses using AI:
OFF
Tags
CCSS.HSF.LE.A.4
5.
FILL IN THE BLANK QUESTION
15 mins • 1 pt
The organizers of a single-elimination tennis tournament created a table that relates the number of matches played in the tournament, x, and the number of rounds in the tournament, y. Enter a logarithmic expression that is equivalent to y in the box below.
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Which of the following functions BEST represents positive exponential growth?
f(x) = 6 * (8/7)^x
f(x) = 4 * (3/4)^x
f(x) = -5 * (1/3)^x
f(x) = -3/2 * 5^x
Tags
CCSS.HSF-IF.C.8B
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A scientist is studying how bacteria thrive under different conditions of temperature and pressure. The scientist develops bacteria population models for the different conditions, as shown below. The models predict the bacteria population, P, after t hours. - Condition 1: P(t) = 500(0.3)^t - Condition 2: P(t) = 500(1.65)^t - Condition 3: P(t) = 500(0.95)^t - Condition 4: P(t) = 500(0.2)^t Which condition models an exponential growth of the bacteria population over time?
P(t) = 500(0.3)^t
P(t) = 500(1.65)^t
P(t) = 500(0.95)^t
P(t) = 500(0.2)^t
Tags
CCSS.HSF.LE.A.2
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