Hardy-Weinberg & Population Genetics

p + q = 1. If p represents the dominant allele frequency, what would q represent?

• the homozygous dominant genotype frequency

• the recessive allele frequency

• the total amount of alleles in the population

• a measure of fitness in the population

The gene pool for a population of 10 individuals contains 4 recessive alleles and 16 dominant alleles (20 alleles total). What is the value for p (dominant allele frequency)?

Tags

NGSS.HS-LS4-3

In a gene pool for a population of 30 individuals, there are 40 recessive alleles and 20 dominant alleles. What is the value for q? (round to hundredths place)

Tags

NGSS.HS-LS3-3

0.49 + 2pq + 0.09 =1 Find the value for 2pq.

Tags

NGSS.HS-LS4-3

In the Hardy-Weinberg Equation, q² is the frequency of what?

• The recessive allele 

• the dominant allele

• the recessive genotype

• the dominant genotype

Tags

NGSS.HS-LS4-3

In the Hardy-Weinberg Equation, p² is the frequency of what?

• The recessive allele 

• the dominant allele

• the recessive genotype

• the dominant genotype

A rather large population of foxes has 555 individuals with tan fur and 390 individuals with red fur. Assume that red is recessive.

What should you try to start with?

• p

• q

• q²

• p²

Tags

NGSS.HS-LS4-3

If the frequency of recessive allele is 0.2, what is the frequency of the homozygous recessive individuals?

• 0.04

• 0.16

• 0.4

• 0.8

Answer explanation

The frequency of homozygous recessive individuals is 0.04, which is calculated by squaring the frequency of the recessive allele (0.2 x 0.2 = 0.04).

The allele frequency of p=.20 What is the frequency of the heterozygous genotype?

• .80

• .04

• .32

• .64

Answer explanation

This is a 2 step qestion.

1. Find q by plugging in p to the equation p + q = 1. You should get q = 0.8

2. Plug in p and q to 2pq to find the heterozygous frequency. 2(0.2)(0.8) = 0.32

Tags

NGSS.HS-LS3-3

A population of 150 individuals has an allele frequency of 0.3 for the dominant allele (B) and a frequency of 0.7 for the recessive allele (b). Use the Hardy-Weinberg equation to determine the frequency of the genotype (bb).

• 0.09

• 0.42

• 0.49

• 0.21

Answer explanation

This question gives you p and q. It is asking you to find the recessive genotype, which is q². Use q (0.7) and square it to find the correct answer.

(0.7)² or 0.7 x 0.7 = 0.49