Sam Eagers Mathematical Problems

If Sam eager has a 740000000 highlighters. how would you write that in scientific notation?

• -7.4 x 10^8

• 7.4 x 10^8

• 74x10^8

• 7.4+10^8

Sam Eager made this monstrosity. but he has forgotten what each part is called. can you help him?

a

c

b

axis of symetry

vertex / y intercept

x-intercept 1

Sam Eager has 750 pears. but he's a maths teacher so he thinks it would be funny to tell people he has that number in scientific notation. but he forgot scientific notation. explain how to do scientific notation in a few sentences.

draw a graph with the function y=3x²-2

then draw the inverse function in a different colour.

if ​ Sam Eager has has ​ (a)   eagergrams and sam lee has ​ (b)   eagergrams then Sam Eager has 86.6 as many eagergrams as Sam Lee

• 7.8x10^6
• 9x10^4
• 7.5x10^5
• 9.3x10^3
• 6.75x10^5

if 2.5 x 10^-6 is the scientific notation for the number of 1kg curls Sam Lee can do in a minute. how long would it take him to do 1 curl rounded to the nearest hour?

• 407,000

• 425,000

• 419,000

• 400,000

Sam Lee used to do 7.8x10^-7 pushups in a hour. Now he does triple the pushups in a hour, if he wants to do three pushups while having a 2 kilo weight on his back, which slows him down by 25%. How long would it take him in hours.

• 1,678,107

• 1,700,430

• 1,709,401

• 1,696,892

Answer explanation

1. Determine Sam's original pushup rate:

   • Sam used to do 7.8×10−77.8 \times 10^{-7}7.8×10−7 pullups in an hour.

   • Now he does triple the pushups: 3×7.8×10−73 \times 7.8 \times 10^{-7}3×7.8×10−7 pushups in an hour.

   • Therefore, Sam's pushup rate without any weight is 2.34×10−62.34 \times 10^{-6}2.34×10−6 pushups per hour.

2. Adjust for the weight on his back:

   • The 2 kilo weight slows him down by 25%.

   • Therefore, with the weight, his pushup rate is reduced to 75%75\%75% of his original rate.

   • New rate = 0.75×2.34×10−60.75 \times 2.34 \times 10^{-6}0.75×2.34×10−6 pushups per hour.

   • Calculating the new rate:

New rate=0.75×2.34×10−6=1.755×10−6 pushups per hour\text{New rate} = 0.75 \times 2.34 \times 10^{-6} = 1.755 \times 10^{-6} \text{ pushups per hour}New rate=0.75×2.34×10−6=1.755×10−6 pushups per hour

3. Calculate the time to do three pushups:

   • We need to find out how long it takes to do 3 pushups at this new rate.

   • Time = Number of pushupsPushup rate\frac{\text{Number of pushups}}{\text{Pushup rate}}Pushup rateNumber of pushups​

   • Therefore, Time = 3 pushups1.755×10−6 pushups per hour\frac{3 \text{ pushups}}{1.755 \times 10^{-6} \text{ pushups per hour}}1.755×10−6 pushups per hour3 pushups​