
Photoelectron Spectroscopy (PES)
Authored by Lauren Peterson
Chemistry
University
NGSS covered
Used 436+ times

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14 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which element has the electron configuration 1s22s22p63s23p5?
chlorine
fluorine
sulfur
phosphorus
Tags
NGSS.HS-PS1-1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many peaks would you see for the PES graph for the element with an electron configuration of 1s22s22p63s1
2
3
4
5
Tags
NGSS.HS-PS1-1
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the electron configuration for this PES graph?
1s22s22p63s23p2
1s22s22p63s23p1
1s22s22p63s23p3
1s22s22p63s2
Tags
NGSS.HS-PS1-1
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which element is represented by this PES graph?
aluminum
phosphorus
sulfur
silicon
Tags
NGSS.HS-PS1-1
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which element is represented by this PES graph?
argon
potassium
calcium
scandium
Tags
NGSS.HS-PS1-1
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which element is represented by this PES graph?
calcium
potassium
titanium
scandium
Tags
NGSS.HS-PS1-1
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
The photoelectron spectra above show the energy required to remove a 1s electron from a nitrogen atom and from an oxygen atom. Which of the following statements best accounts for the peak in the upper spectrum being to the right of the peak in the lower spectrum?
Nitrogen atoms have a half-filled p subshell.
There are more electron-electron repulsions in oxygen atoms than in nitrogen atoms.
Electrons in the p subshell of oxygen atoms provide more shielding than electrons in the p sub shell of nitrogen atoms.
Nitrogen atoms have a smaller nuclear charge than oxygen atoms.
Answer explanation
"Nuclear charge" = charge of the nucleus. A greater nuclear charge will result in a greater attraction to the 1s electrons, and therefore more energy will be required to remove those electrons.
Tags
NGSS.HS-PS1-1
NGSS.HS-PS1-2
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