CCSS.Math.Content.HSG.SRT.C.6

Solve for x

• 66
• 114
• 56
• 106

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CCSS.Math.Content.HSG.SRT.C.6

In this 45-45-90 triangle, I have been given a leg, so to find the other leg I...

• Multiply that leg by 2
• Use the same length for the second leg
• Multiply that leg by √2
• Divide that leg by √2

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CCSS.Math.Content.HSG.SRT.C.6

What type of special triangle is this?

• 45°-45°-90°
• 30°-60°-90°
• Equiangular
• Equilateral

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CCSS.Math.Content.HSG.SRT.C.6

What is the measure of side c?

• 6
• 6√2
• 6√3
• 12

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CCSS.Math.Content.HSG.SRT.C.6

Find the value of x.

• 18
• 18√3
• 36√3
• 12

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CCSS.Math.Content.HSG.SRT.C.6

Find a - the length of a leg of the triangle.

• 5
• √2
• 5√2
• 2

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CCSS.Math.Content.HSG.SRT.C.6

What is the length of y in this 45-45-90 triangle?

• 8√2
• 4√2
• 4
• 8

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CCSS.Math.Content.HSG.SRT.C.6

I am an angle that measures

exactly 90 degrees. Who am I?

• acute

• obtuse

• right

• straight

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CCSS.Math.Content.HSG.SRT.C.6

Identify the trig ratio that may be used to find the marked unknown angle.

•  $Sin\ y\degree=\frac{12}{18}$  

•  $Cos\ y\degree\ =\ \frac{18}{12}$ 

•  $Cos\ y\degree\ =\ \frac{12}{18}$ 

•  $Tan\ y\degree=\ \frac{12}{18}$ 

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CCSS.Math.Content.HSG.SRT.C.6

Identify the trig ratio that may be used to find the marked unknown side.

• $Sin\ 38\degree=\frac{w}{15}$

• $Cos\ 38\degree\ =\ \frac{15}{w}$

• $Tan\ 38\degree\ =\ \frac{w}{15}$

• $Sin\ 38\degree=\ \frac{15}{w}$

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CCSS.Math.Content.HSG.SRT.C.6