TEKS.MATH.9-12.II.C

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Tags

TEKS.MATH.9-12.II.C

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)
• (-4, -1) and (2, 5)
• (2, -1 and (-4, 5)
• (-4, 1) and (2, -1)

Tags

TEKS.MATH.9-12.II.C

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Tags

TEKS.MATH.9-12.II.C

Solve using Zero-Product Property.
(2x-2)(5x-5) = 0

• x = -1
• x = -1 or x = 1
• x = 1

Tags

TEKS.MATH.9-12.II.C

y varies inversely as x, if y = -3 when x = -6, find y when x = 14.

• 11
• -11
• 9/7
• 7/9

Tags

TEKS.MATH.9-12.II.C

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Tags

TEKS.MATH.9-12.II.C

What is the Range of the situation?

• All real numbers greater than or equal to 0 and less than or equal to 28
• All real numbers greater than or equal to 0 and less than or equal to 9
• All real numbers less than or equal to 28
• All real numbers less than or equal to 9

Tags

TEKS.MATH.9-12.II.C

Solve using Zero-Product Property.
(2x-2)(5x-5) = 0

• x = -1
• x = -1 or x = 1
• x = 1

Tags

TEKS.MATH.9-12.II.C

2(x - 8)² + 40 = 16

• x = 8 ± 2i√3

• x = 8 ± √-12

• x = -8 ± 2i√3

• x = 8 ± 3i√2

Tags

TEKS.MATH.9-12.II.C

P = a + (n - 1)b

Solve for b

• $b=\frac{P-a}{n-1}$

• $b=\frac{P}{a+\left(n-1\right)}$

• $b=\frac{P}{a}-\left(n-1\right)$

• $b=\frac{P}{n-1}-a$

Tags

TEKS.MATH.9-12.II.C