How did we transform from the parent function? y = x 2 + 2

Kvadratinė funkcija Quiz

13 questions

Show all answers

1.

GRAPHING QUESTION

3 mins • 1 pt

Nubrėžk kvadratinės funkcijos grafiką.

2.

GRAPHING QUESTION

3 mins • 1 pt

Nubrėžk kvadratinės funkcijos grafiką.
$y=-\frac{1}{4}x^2$

3.

MATH RESPONSE QUESTION

2 mins • 1 pt

$A\left(1,5;\ 9\right)$

$y=4x^2$

Mathematical Equivalence

ON

4.

MATH RESPONSE QUESTION

2 mins • 1 pt

$A\left(-\frac{\sqrt[]{2}}{7};14\right)$

$y=343x^2$

Mathematical Equivalence

ON

5.

MATH RESPONSE QUESTION

2 mins • 1 pt

$A\left(\frac{3}{10};-4\right)$

$y=-\frac{400}{9}x^2$

Mathematical Equivalence

ON

6.

MATH RESPONSE QUESTION

2 mins • 1 pt

Užrašykite formule funkciją $f\left(x\right)=ax^2$ , kurios grafikui priklauso taškas A:

$y=\frac{5}{4}x^2$

Mathematical Equivalence

ON

7.

MATH RESPONSE QUESTION

2 mins • 1 pt

$f\left(-2\right)=$

$-\frac{8}{5}$

Mathematical Equivalence

ON

8.

MATH RESPONSE QUESTION

2 mins • 1 pt

$f\left(1,5\right)=$

$-\frac{9}{10}$

Mathematical Equivalence

ON

9.

MATH RESPONSE QUESTION

2 mins • 1 pt

$f\left(\frac{\sqrt[]{3}}{8}\right)=$

$-\frac{9}{160}$

Mathematical Equivalence

ON

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$A\left(1,5;\ -4,05\right)$

Priklauso

Nepriklauso

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Kvadratinė funkcija

Nubrėžk kvadratinės funkcijos grafiką.

Nubrėžk kvadratinės funkcijos grafiką. y=−14x2y=-\frac{1}{4}x^2y=−41​x2

A(1,5; 9)A\left(1,5;\ 9\right)A(1,5; 9)

A(−27;14)A\left(-\frac{\sqrt[]{2}}{7};14\right)A(−72​​;14)

A(310;−4)A\left(\frac{3}{10};-4\right)A(103​;−4)

Užrašykite formule funkciją f(x)=ax2f\left(x\right)=ax^2f(x)=ax2 , kurios grafikui priklauso taškas A:

f(−2)=f\left(-2\right)=f(−2)=

f(1,5)=f\left(1,5\right)=f(1,5)=

f(38)=f\left(\frac{\sqrt[]{3}}{8}\right)=f(83​​)=

A(1,5; −4,05)A\left(1,5;\ -4,05\right)A(1,5; −4,05)

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Discover more resources for Mathematics

Nubrėžk kvadratinės funkcijos grafiką.
$y=-\frac{1}{4}x^2$

$A\left(1,5;\ 9\right)$

$A\left(-\frac{\sqrt[]{2}}{7};14\right)$

$A\left(\frac{3}{10};-4\right)$

Užrašykite formule funkciją $f\left(x\right)=ax^2$ , kurios grafikui priklauso taškas A:

$f\left(-2\right)=$

$f\left(1,5\right)=$

$f\left(\frac{\sqrt[]{3}}{8}\right)=$

$A\left(1,5;\ -4,05\right)$