I can clear radicals / roots from the denominator of a fraction by:

Multiplying by 1 in the form of $$\frac{\sqrt[]{a\ number}}{\sqrt[]{a\ number}}$$

Adding 1 in the form of $$\frac{\sqrt[]{a\ number}}{\sqrt[]{a\ number}}$$

If I have an expression with a radial / root in the denominator (e.g. $$\frac{17}{2+\sqrt[]{3}}$$ ), I can clear it by

Multiplying by 1 in the form of $$\frac{2-\sqrt[]{3}}{2-\sqrt[]{3}}$$

Multiplying by 1 in the form of $$\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}$$

When graphing slope (m):

If m>0, the line goes up and to the right. If m<0, the line goes down and to the left

The slope (m) is a function of time

If m<0, the line goes up and to the right. If m>0, the line goes down and to the left

When a negative number is MULTIPLIED or DIVIDED across an inequality (<,>), I must:

Flip the direction of the inequality sign

Ignore the negative sign and circle the wrong answer

Huh, what? I wasn't paying attention

For a parabola / quadratic $$\left(y=ax^2+bx+c\right)$$ ...

When a>0, the parabola is concave up. When a<0, the parabola is concave down.

When b>0, the parabola is concave up. When b<0, the parabola is concave down.

When b<0, the parabola is concave up. When b>0, the parabola is concave down.

When a<0, the parabola is concave up. When a>0, the parabola is concave down.

The vertex form of a parabola / quadratic is:

$$y=a\left(x-h\right)^2+k$$ where (h,k) is the vertex

$$y=a\left(x+h\right)^2-k$$ where (h,k) is the vertex

$$y=a\left(x+h\right)^2-k$$ where (k,h) is the vertex

$$y=a\left(x-h\right)^2+k$$ where (k,h) is the vertex

The radius (r) of a circle is:

A line from the center of the circle to any outer edge

The distance around the edge of the circle

A line from the one edge of the circle to the opposite edge (through the center of the circle)

To find the nth value in a series, I can use

$$Original\ value\ +\ \left(n-1\right)\cdot d$$ where (d) is the constant difference between terms

$$Original\ value\ -\ \left(n-1\right)\cdot d$$ where (d) is the constant difference between terms

$$Original\ value\ -\ \left(n+1\right)\cdot d$$ where (d) is the constant difference between terms

$$Original\ value\ -\ \left(n-1\right)\cdot d$$ where (d) is the constant difference between terms

To calculate exponential growth or decay, I use

Value at time (t) = $$Starting\ value\ \cdot\left(1+rate\right)^{time\ periods}$$

Value at time (t) = $$Starting\ value\ \cdot1^{time\ periods}$$

Value at time (t) = $$Starting\ value\ +1^{time\ periods}$$

Value at time (t) = $$Starting\ value\ +\left(1+rate\right)^{time\ periods}$$

If I take a random sample and make a finding, that finding may ONLY apply to:

The EXACT population that I took the sample from

A wider population than that from which the sample was taken

Standard deviation is

The measure of how spread out data is (how far from the average)

The middle value when data is arranged from least to greatest

The most common value in a data set

All the sides (and thus the interior angles) in a shape are the same

All the interior angles in a shape are the same

The same size and shape (i.e. identical)

Having the same interior angle measurements

The equation of a circle is:

$$\left(x-h\right)^2+\left(y-k\right)^2=r^2$$ where (h,k) is the center and (r) is the radius

$$\left(x-h\right)^2-\left(y+k\right)^2=r^2$$ where (h,k) is the center and (r) is the radius

$$\left(x-h\right)^2-\left(y-k\right)^2=r^2$$ where (k,h) is the center and (r) is the radius

$$\left(x-h\right)^2+\left(y-k\right)^2=r^2$$ where (k,h) is the center and (r) is the radius

Triangles are NOT necessarily congruent (identical) when which of the following matches:

2x sides and the third interior angle

2x interior angles and the third side

The slope of parallel lines will be

The negative inverse of each other

The Remainder Theorem for polynomials $$e.g.\ \frac{x^3+4x^2-5x-14}{x-2}$$ states:

When dividing a polynomial by an expression (x-a), you can substitute the x-value that makes the expression equal zero into the ORIGINAL POLYNOMIAL to determine the remainder

There's no way to determine the remainder except to do long-form synthetic division

The remainder of dividing $$\frac{x^3-4x^2-7x+10}{x-2}$$ is:

-12 using the Remainder Theorem

-8 using Synthetic Long Division

-12 using Synthetic Long Division

The angle formed between a line tangent to the edge of a circle and the radius extending to the same point is equal to

90 degrees - the lines are perpendicular

180 degrees - the lines are perpendicular

90 degrees - the lines form a joint transversable pair

180 degrees - the lines form a joint transversable pair

When a triangle is inscribed in a circle and the diameter is the hypotenuse of the circle...

The angle opposite the hypotenuse = 90 degrees

The angle opposite the hypotenuse = 135 degrees

The angle opposite the hypotenuse = 45 degrees

When I see a word problem...

I should convert the words to an equation

I should just try to do it in my head

When I see a function [f(x)]...

I can take an x-value and plug it in to determine the y-value. Each x-value may only produce one y-value for it to classify as a function

When I see a radical sign or an absolute value sign in a problem...

I should be extremely careful because there may be two solutions (positive and negative)

I should work the problem faster

When a distribution graph is "skewed right", the majority of the data will be

To the left side of the graph and the median will be less than the mean

To the right side of the graph and the median will be greater than the mean

If given the averages of Group A and Group B, I can get the average of Groups A+B by averaging the two averages

False - I have to use the formula to calculate the mean (average)

When I see a negative sign in front of an expression e.g. ( $$x-\left(14-8\right)$$ ), I should be careful

True - the negative sign needs to be distributed across both the +14 and the -8

In order to add fractions...

The denominator must be the same - and it stays the same after the numerators are added

The denominator must be the same - and it doubles after the numerators are added

As an alternative to dividing by a fraction, I can...

Multiply by the inverse (flip and multiply)

If I have two fractions that equal each other...

I can cross-multiply (whole numbers can be written as fractions / 1)

Multiplying both sides by 1 is a great idea

The point-slope formula of a line is:

$$y-y_1=m\left(x-x_1\right)$$ for any slope (m) and point on the line $$\left(x_1,y_1\right)$$

$$y=mx+b$$ for any slope (m) and y-intercept (b)

$$y+y_1=m\left(x+x_1\right)$$ for any slope (m) and point on the line $$\left(x_1,y_1\right)$$

$$y-y_1=m\left(x+x_1\right)$$ for any slope (m) and point on the line $$\left(x_1,y_1\right)$$

The formula for slope is

$$\frac{y_2-y_1}{x_2-x_1}$$ for any two points on a line $$\left(x_1,y_1\right)$$ and $$\left(x_2,y_2\right)$$

$$\frac{y_1-y_2}{x_2-x_1}$$ for any two points on a line $$\left(x_1,y_1\right)$$ and $$\left(x_2,y_2\right)$$

$$\frac{y_2+y_1}{x_2-x_1}$$ for any two points on a line $$\left(x_1,y_1\right)$$ and $$\left(x_2,y_2\right)$$

$$\frac{y_2-y_1}{x_1-x_2}$$ for any two points on a line $$\left(x_1,y_1\right)$$ and $$\left(x_2,y_2\right)$$

How can I solve a system of equations (2x equations with 2 variables (x and y)?

Substitution (Solve 1 equation for x, then replace (substitute) the value that equals x in the place of the x in the second equation)

Elimination (Add or subtract the left and right sides of the equations in order to "eliminate" (e.g. -2x +2x) one of the variables)

Use the system of equations program in my calculator

Use my creativity and just try something random

The Triangle Inequality Theorem states

The sum of any two sides of a triangle is always GREATER than the length of the third side

The sum of any two sides of a triangle is always LESS than the length of the third side

The product of any two sides of a triangle is always GREATER than the length of the third side

The product of any two sides of a triangle is always LESS than the length of the third side

I can calculate the sum of the interior angles of a polygon using...

$$\left(n-2\right)\cdot180\degree$$ where n = number of side of the polygon

$$\left(n-1\right)\cdot180\degree$$ where n = number of side of the polygon

$$\left(n-2\right)\cdot360\degree$$ where n = number of side of the polygon

$$\left(n-1\right)\cdot360\degree$$ where n = number of side of the polygon

For a parabola / quadratic ( $$y=ax^2+bx+c$$ ), the discriminant ( $$b^2-4ac$$ ) tells me what?

If >0 The parabola crosses the x-axis in 2x places (aka has 2x roots)

If =0 The parabola touches the x-axis in 1x place (aka has 1x root)

If <0 The parabola does not cross the x-axis (aka has no roots)

If <0 The parabola crosses the x-axis in 2x places (aka has 2x roots)

If I need to find the mid-way point between two points in the xy-plan, I can use

The average of the x-values $$\frac{x_1+x_2}{2}$$ for x and the average of the y-values $$\frac{y_1+y_2}{2}$$ for y

The mid-point program on my calculator

The average of the x-values $$\frac{x_1-x_2}{2}$$ for x and the average of the y-values $$\frac{y_1-y_2}{2}$$ for y

Polygons are similar when

The interior angles are the same and... the proportions of the sides to one another are the same

When two lines intersect...

The angles formed opposite to each other will be equal

The angles next to each on a straight line will sum to 180 degrees

The angles formed opposite to each other will sum to 180 degrees

The angles next to each on a straight line will equal each other

Standardized Test Prep - Math

Authored by M C

Mathematics

11th Grade

CCSS covered

Used 1+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.HSA.SSE.B.3

CCSS.HSN.RN.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The sum of the exterior angles of any polygon is:

240 degrees

360 degrees

450 degrees

180 degrees

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The Inscribed Angle Theorem states that

A central angle will be HALF as large as an angle inscribed with the same points

A central angle will be TWICE as large as an angle inscribed with the same points

Tags

CCSS.HSG.C.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The formula for area of a circle is:

Tags

CCSS.7.G.B.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The arc length of a circle is:

Tags

CCSS.HSG.C.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The area of a sector (pie slice) of a circle is

Tags

CCSS.HSG.C.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

I should write ratios and unit conversions as:

I'll just do it in my head

Ratios with a colon separator

I don't need to show my work

Tags

CCSS.6.RP.A.3B

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Standardized Test Prep - Math

The sum of the exterior angles of any polygon is:

The Inscribed Angle Theorem states that

The formula for area of a circle is:

The arc length of a circle is:

The area of a sector (pie slice) of a circle is

I should write ratios and unit conversions as:

The formula for distance is

I can clear radicals / roots from the denominator of a fraction by:

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