U2: Electronegativity: Mastery Test

Which pair of molecules is not a polar bond?

• A. N – O

• B. C – O

• C. O – H

• D. O – O

Use the chart to determine which pair of atoms has the greatest difference in electronegativity.

• Ca – Cl

• H – Cl

• Fe – Cl

• P – Cl

Select the correct answer. Use the chart to determine which pair of atoms has the greatest polarity.

• Al – Si

• S – Cl

• N – H

• C – N

Tags

NGSS.HS-PS1-2

Use the chart to determine which type of bond is formed between potassium (K) and chlorine (Cl).

• nonpolar covalent

• moderately polar covalent

• highly polar covalent

• ionic

Tags

NGSS.HS-PS1-1

NGSS.HS-PS1-2

Select the correct answer. Use the chart to determine which is an example of a highly polar covalent bond.

• Ca – Cl

• Fe – O

• H – S

• F – F

Select the correct answer. The elements found in Group 2A, from top to bottom, include beryllium, magnesium, calcium, strontium, and barium. Which of these elements has the highest electronegativity value?

• beryllium

• magnesium

• calcium

• barium

Tags

NGSS.HS-PS1-1

NGSS.HS-PS1-2

Use the chart to determine which pairs of atoms are arranged in the correct order according to increasing bond polarity?

• H – Cl < H – F < H – O < H – S

• H – S < H – Cl < H – O < H – F

• H – O < H – S < H – Cl < H – F

• H – F < H – O < H – Cl < H – S

Select the correct answer. Use the chart to determine which atom in the carbon–chlorine bond is assigned the delta negative charge.

• carbon atom

• chlorine atom

• neither atom

• both atoms

Tags

NGSS.HS-PS1-1

Select the correct answer. Which statement is true?

• A molecule having a covalent bond can be ionic.

• A molecule having a covalent bond is always polar.

• A molecule having a covalent bond may be polar or nonpolar.

• A molecule having a covalent bond is always nonpolar.

The molecule hydrogen fluoride (HF) contains a polar bond H – F, where fluorine is more electronegative than hydrogen. Which is the appropriate representation of the H – F bond?

• H – F⁺

• H⁺ – F⁻

• δ⁺H – δ⁺F

• δ⁺H – δ⁻F