BIOC*3560 - Part A, Regulation of Protein Function

Quiz
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Science
•
University
•
Easy
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45 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A ______ is a molecule that is permanently
associated with a protein and required for its function. This is considered a _____ interaction.
ligand, stable
prosthetic group, stable
ligand, transient
prosthetic group, transient
2.
FILL IN THE BLANK QUESTION
1 min • 1 pt
In sickle cell anemia, Hemoglobin S (HbS) is formed due to a single amino acid substitution in which _____ on the ___-globin is changed to _____.
Type answer as ABC X(Y)1, alpha or beta, banana (name the amino acid)
3.
FILL IN THE BLANK QUESTION
1 min • 1 pt
________ mediates the reaction converting ___ to ___ in the ____, decreasing the pH.
Answer explanation
Recall decreasing the pH makes the tissues more acidic.
4.
OPEN ENDED QUESTION
3 mins • 1 pt
What are the two reasons why the affinity of CO to bind to heme decreases when heme is bound in an oxygen-binding protein such as Myoglobin or Hemoglobin?
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Answer explanation
Steric hindrance between His E7 & CO decreases affinity of heme for CO as CO binds straight and kind of bumps into the distal histidine.
Oxygen also binds at an angle creating a favourable bond
5.
OPEN ENDED QUESTION
3 mins • 1 pt
What does Kd represent? Provide its formula and units as well.
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Answer explanation
Kd is the dissociation constant and represents the ligand concentration, [L] at which half of the ligand-binding
sites are occupied. Its units are in concentration (e.g., g/L, molar [M], etc.)
Kd represents when Θ (occupancy) = 0.5
6.
OPEN ENDED QUESTION
3 mins • 1 pt
What does Θ (theta) represent? Provide its formula and units as well.
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Evaluate responses using AI:
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Answer explanation
Occupancy is typically expressed as a ratio and not a percentage!
Occupancy is expressed in terms of variables that WE can manipulate – experimentally ligand concentration is usually altered.
7.
FILL IN THE BLANK QUESTION
1 min • 1 pt
A(n) _______ is the region of a protein surface that interacts with a ligand.
Answer explanation
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