Exploring Explicit and Recursive Formulas in Geometric Sequences

Exploring Explicit and Recursive Formulas in Geometric Sequences

Assessment

Interactive Video

Created by

Mia Campbell

Mathematics

8th - 12th Grade

8 plays

Medium

The video tutorial explains a sequence defined by a function G, where each term is half of the previous term, forming a geometric series. It covers how to define the sequence explicitly and recursively, using algebraic manipulation to show equivalent forms. The tutorial encourages viewers to think about the sequence's properties and how to express it mathematically.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first term of the sequence given in the video?

42

168

21

84

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you go from the first term to the second term in the sequence?

Add 84

Multiply by 1/2

Subtract 84

Divide by 2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of sequence is described in the video?

Geometric

Arithmetic

Fibonacci

Harmonic

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common ratio in the geometric series described?

1/2

1/4

2

1/3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can the explicit formula for G(n) be written?

168 * (1/2)^(n-1)

168 - (1/2)^(n-1)

168 + (1/2)^(n-1)

168 / (1/2)^(n-1)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of G(3) in the sequence?

42

84

21

168

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can the explicit formula be algebraically manipulated?

168 / 2^(n-1)

168 * 2^(n-1)

168 + 2^(n-1)

168 - 2^(n-1)

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the recursive definition for G(n) when n > 1?

G(n) = G(n-1) + 1/2

G(n) = 2 * G(n-1)

G(n) = G(n-1) - 1/2

G(n) = 1/2 * G(n-1)

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial value for G(1) in the recursive definition?

168

84

21

42

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you verify the recursive definition for G(2)?

G(2) = 2 * G(1)

G(2) = 1/2 * G(1)

G(2) = G(1) + 1/2

G(2) = G(1) - 1/2

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