The video tutorial covers section 8.1, focusing on solving practice problems using ratios and cross multiplication. The instructor demonstrates solving two problems, finding the ratio of X to Y and A to B, using the means extremes product theorem. Students are then encouraged to solve problems 3 and 4 independently, focusing on arithmetic and geometric means, and finding the fourth proportional term.

What is the first step in solving the ratio of X to Y?

• Add the terms on both sides

• Cross multiply

• Divide both sides by Y

• Subtract Y from both sides

What is the reduced form of the ratio 15 to 5?

• 15 to 1

• 1 to 3

• 3 to 1

• 5 to 1

Tags

CCSS.6.RP.A.1

CCSS.6.RP.A.2

In the ratio of A to B, what should you remember to do with a binomial?

• Add it to both sides

• Subtract it from both sides

• Put parentheses around it and distribute

• Ignore it

Tags

CCSS.7.RP.A.3

What is the final reduced ratio of A to B?

• 3 to 1

• 3 to 2

• 2 to 1

• 1 to 2

Tags

CCSS.6.RP.A.1

CCSS.6.RP.A.2

What should you do after solving problems 3 and 4 on your own?

• Submit your answers

• Compare your answers with the provided solutions

• Ask the teacher for help

• Redo the problems

Tags

CCSS.6.EE.A.1

What is the arithmetic mean of the given numbers in problem 3?

• 20

• 15

• 10

• 5

Tags

CCSS.7.EE.B.3

How should you set up the geometric mean?

• As a difference

• As a quotient

• As a sum

• As a product

What should you remember to list for the geometric mean?

• Neither option

• Only the positive option

• Both positive and negative options

• Only the negative option

What is the fourth term or fourth proportional in problem 4?

• 4

• 5

• 6

• 7

What is the final value of X after cross multiplying in problem 4?

• 7

• 6

• 5

• 4

Tags

CCSS.6.RP.A.3C