Exploring Parametric Equations: Beginnings Part 2

Exploring Parametric Equations: Beginnings Part 2

Assessment

Interactive Video

Created by

Mia Campbell

Mathematics

9th - 12th Grade

Hard

The video tutorial covers the basics of parametric equations, including how to eliminate parameters using trigonometric identities and algebra. It provides examples of converting parametric equations to standard forms, such as circles and parabolas, and demonstrates methods to create parametric equations from standard equations. The tutorial concludes with a brief mention of further calculus topics.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the radius of the circle derived from the parametric equations x = 2 cos(θ) and y = 2 sin(θ)?

2

1

4

3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric identity is used to eliminate the parameter in the equations x = 2 cos(θ) and y = 2 sin(θ)?

sin(2θ) = 2 sin(θ) cos(θ)

1 / cos(θ) = sec(θ)

sin(θ) / cos(θ) = tan(θ)

sin^2(θ) + cos^2(θ) = 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard form equation derived from x = 2 cos(θ) and y = 2 sin(θ)?

x^2 + y^2 = 2

x^2 - y^2 = 2

x^2 - y^2 = 4

x^2 + y^2 = 4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the equation x^2 + y^2 = 4 represent?

An ellipse

A parabola

A hyperbola

A circle

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you solve for 't' from the equation x = 3/2 t?

t = 3/2x

t = x/3

t = 3x/2

t = 2x/3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the resulting equation for y when substituting t = 2/3 x into y = 4 - 3/4 t^2?

y = 4 - 1/3 x^2

y = 4 + 3/2 x^2

y = 4 + 1/3 x^2

y = 4 - 3/2 x^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplest form of parametric equations for y = 6x^2 - 1?

x = t, y = 6t^2 - 1

x = t^2, y = 6t - 1

x = t, y = 6t - 1

x = t^2, y = 6t^2 - 1

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What alternative parametric form can represent y = 6x^2 - 1?

x = 1/3 t, y = 6(1/3 t)^2 - 1

x = t/3, y = 18t^2 - 1

x = 3t, y = 54t^2 - 1

x = t/3, y = 2t^2 - 1

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which method is described as 'arbitrary' for creating parametric equations?

Using trigonometric identities

Solving a quadratic equation

Defining x as a function of t and substituting in y

None of the above

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary reason for converting standard equations into parametric form as mentioned in the video?

For educational purposes

To facilitate graphing

None of the above

To simplify calculations

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