Solving Systems of Equations by Substitution

Solving Systems of Equations by Substitution

Assessment

Interactive Video

Mathematics

8th - 12th Grade

Medium

Created by

Jackson Turner

Used 13+ times

FREE Resource

Professor Von Schmohawk introduces a lecture on finding the intersection point of two graphs, using the tortoise and hare race as an example. The lecture focuses on the substitution method to solve a system of equations, demonstrating how to find the exact time and distance when the tortoise and hare meet. The process involves substituting one equation into another to solve for variables, verifying the solution, and converting results into mixed numbers. The lecture concludes with a preview of the elimination method for solving equations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the hare doing during the first four hours of the race?

Sleeping

Reading an Algebra book

Running at full speed

Waiting at the starting point

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At what time did the hare overtake the tortoise?

Between 5 and 6 hours

Exactly at 4 hours

Before 5 hours

After 6 hours

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the purpose of graphing the distances of the tortoise and hare?

To determine who won the race

To identify the point where they meet

To illustrate their starting points

To find the speed of each racer

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which mathematical method is demonstrated to find the intersection point?

Elimination

Integration

Graphing

Substitution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the value of 'y' equal according to the second equation?

The square of x

x minus 2

Two times x

One-half of x

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final value of x found through substitution?

Twelve-thirds

Four-thirds

Eight-thirds

Sixteen-thirds

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the value of y determined after finding x?

By adding x to sixteen-thirds

By setting x in the first equation

By multiplying x with two

By setting x in the simplest equation

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