JMAP - Lines and Angles

• 11°

• 43°

• 75°

• 105°

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.CO.C.9

• 42.5°

• 68.75°

• 95°

• 137.5°

Answer explanation

Since line ABC is parallel to line CGD, <CBF and <EBF are corresponding angles. Therefore, m∠EBF = m∠CBF = 42.5°. However, since line segment BF is congruent to line segment EF, <EBF is supplementary to <CBF, giving m∠EBF = 180° - 42.5° = 137.5°. Thus, m∠EBF = 68.75°.

• 118°

• 68°

• 62°

• 56°

Tags

CCSS.HSG.CO.C.9

• 18°

• 48°

• 66°

• 114°

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.CO.C.9

Tags

CCSS.HSG.CO.C.9

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.CO.C.11

CCSS.HSG.SRT.B.4

• ∠ CFG ≅ ∠ FCB

• ∠ ABF ≅ ∠ BFC

• ∠ EFB ≅ ∠ CFB

• ∠ CBF ≅ ∠ GFC

Tags

CCSS.HSG.CO.C.9

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.B.7

CCSS.HSG.CO.C.10

CCSS.HSG.CO.D.12

CCSS.HSG.SRT.B.5

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.9

CCSS.HSG.GPE.B.5

Segment CD is the perpendicular bisector of AB at E. Which pair of segments does not have to be congruent?

• AD,BD

• AC,BC

• AE,BE

• DE,CE

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.C.9