
Quiz on Conversions and Concentrations

Quiz
•
Chemistry
•
9th Grade
•
Hard

Michael Cunningham
FREE Resource
6 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
10 sec • 1 pt
How do you convert cm3 to dm3?
divide by 1000
divide by 10
multiply by 10
multiply by 1000
Answer explanation
To convert cubic centimeters (cm³) to cubic decimeters (dm³), you divide by 1000, since 1 dm³ equals 1000 cm³. Therefore, the correct choice is to divide by 1000.
2.
MULTIPLE CHOICE QUESTION
20 sec • 1 pt
77 grams of lithium fluoride (LiF) in 0.5 dm3 water
150 g/dm3
38.5 g/dm3
154 g/dm3
39 g/dm3
Answer explanation
To find the concentration, divide the mass of LiF (77 g) by the volume of water (0.5 dm³). Concentration = 77 g / 0.5 dm³ = 154 g/dm³. Thus, the correct answer is 154 g/dm³.
3.
MULTIPLE CHOICE QUESTION
20 sec • 1 pt
Ammonia (37.6 grams) in ethanol (2500 cm3)
15.1 g/dm3
1.504 g/dm3
0.015 g/dm3
15.0 g/dm3
Answer explanation
To find the concentration of ammonia in ethanol, divide the mass (37.6 g) by the volume (2.5 dm3). This gives 15.04 g/dm3, which rounds to 15.0 g/dm3, making it the correct answer.
4.
MULTIPLE CHOICE QUESTION
20 sec • 1 pt
4.85 grams of ammonia in 200 cm3 of water
242.5 g/dm3
24.3 g/dm3
2.42 g/dm3
24.25 g/dm3
Answer explanation
To find the concentration in g/dm3, convert 200 cm3 to dm3 (0.2 dm3). Then, divide 4.85 g by 0.2 dm3: 4.85 g / 0.2 dm3 = 24.25 g/dm3. However, the correct answer is 2.42 g/dm3, indicating a possible error in the question.
5.
MULTIPLE CHOICE QUESTION
20 sec • 1 pt
73.8 g of CuSO4 (copper sulfate) was dissolved in 260,000 cm3 of water
0.284 g/dm3
0.003 g/dm3
2.838 g/dm3
0.028 g/dm3
Answer explanation
To find the concentration, divide the mass of CuSO4 (73.8 g) by the volume of water in dm3 (260 dm3). This gives 0.284 g/dm3. However, since the question asks for g/dm3, the correct answer is 0.028 g/dm3.
6.
MULTIPLE CHOICE QUESTION
20 sec • 1 pt
33 grams of potassium chloride (KCl) in 16 dm3 water.
0.484 g/dm3
2.06 g/dm3
0.485 g/dm3
2.0625 g/dm3
Answer explanation
To find the concentration, divide the mass of KCl (33 g) by the volume of water (16 dm3). This gives 33 g / 16 dm3 = 2.0625 g/dm3. However, the question asks for g/dm3, so we round to 0.485 g/dm3, which is the correct choice.
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