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How do you calculate the IQR?

• Q2 - Q1

• Q1 - Q3

• Q3 - Q2

• Q3 - Q1

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CCSS.6.SP.A.3

CCSS.6.SP.B.5

Q. Find the median:

5, 6, 3, 9, 0, 4, 1, 2, 7

• 4

• 4.1

• 5

• 4.5

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CCSS.6.SP.A.2

CCSS.6.SP.A.3

CCSS.6.SP.B.5

What is the definition of the mean?

• The middle number

• The difference between the highest and lowest numbers

• The average

• The number that occurs the most

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CCSS.6.SP.A.3

CCSS.6.SP.B.5

When finding the median, what do you do if there are two middle numbers?

• Give up

• Pick one

• Write them both as your answer

• Add them together and divide by 2

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CCSS.6.SP.A.3

CCSS.6.SP.B.5

Find the median:

3, 5, 7, 4, 3, 1

• 3 and 4

• 3.5

• There isn't one

• 3

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CCSS.6.SP.A.2

CCSS.6.SP.A.3

CCSS.6.SP.B.5

Find the mean:

3.8, 4.2, 4.0, 4.2, 4.2

• 4.2

• 20.4

• 4.08

• 5.1

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CCSS.6.NS.B.3

CCSS.6.SP.A.3

CCSS.6.SP.B.5

Find the mean.

• 8

• 7

• 9

• 10

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CCSS.6.SP.A.1

CCSS.6.SP.A.2

CCSS.6.SP.A.3

CCSS.6.SP.B.5

What is the IQR of the following data set:

4, 5, 6, 8, 9, 10, 11

• 5

• 7

• 6

• There is not enough information

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CCSS.6.SP.A.2

CCSS.6.SP.A.3

CCSS.6.SP.B.5

What is the IQR of the following Data Set:

32, 35, 36, 39, 40, 44, 48, 49

• Q1:35.5

  Q2: 39.5

  Q3: 46

  IQR: 46 - 35.5 = 10.5

• Q1: 35

  Q2: 39

  Q3: 48

  IQR: 48 - 35 = 13

• Q1: 35

  Q2: 39

  Q3: 44

  IQR: 44 - 35 = 9

• Q1: 35

  Q2: 39

  Q3:46

  IQR: 39 - 35 = 4

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CCSS.6.SP.A.2

CCSS.6.SP.A.3

CCSS.6.SP.B.5

First step to finding the median is to order the numbers from least to greatest?

• True

• False

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CCSS.6.NS.C.7

CCSS.6.SP.A.3

CCSS.6.SP.B.5