Honors Physics Midterm Review

You push a 10 kg cart and it accelerates at 2 m/s². What force did you push with?

• 2 Newtons

• 5 Newtons

• 10 Newtons

• 20 Newtons

Answer explanation

To find the force, use Newton's second law: F = m * a. Here, m = 10 kg and a = 2 m/s². Thus, F = 10 kg * 2 m/s² = 20 N. Therefore, the correct answer is 20 Newtons.

Tags

NGSS.HS-PS2-1

A person has a mass of 24 kg on Earth. What is the persons mass on the Moon (1/6 of Earth's gravity)?

• 24 kg

• 144 kg

• 6 kg

• 4 kg

Answer explanation

Mass is a measure of the amount of matter in an object and does not change with location. Therefore, the person's mass remains 24 kg on the Moon, despite the difference in gravity.

Tags

NGSS.MS-PS2-4

When you know speed and direction you know

• force

• acceleration

• velocity

• momentum

Answer explanation

When you know both speed and direction, you are describing velocity. Velocity is a vector quantity that includes both magnitude (speed) and direction, distinguishing it from other concepts like force or momentum.

Tags

NGSS.HS-PS2-2

The more mass an object has, the faster it will fall.

• True

• False

Answer explanation

The statement is false because, in a vacuum, all objects fall at the same rate regardless of mass due to gravity. Air resistance affects falling speed, but mass alone does not determine how fast an object falls.

Tags

NGSS.MS-PS2-4

What is Newtons 2nd law?

• Kinetic Energy = 1/2mv²

• Work = Force x distance

• Force = Mass x Accelaration

• gravitational potential energy = mass x gravity x height

Answer explanation

Newton's 2nd law states that Force equals Mass times Acceleration (F = ma). This means the force acting on an object is directly proportional to its mass and the acceleration it experiences.

Tags

NGSS.HS-PS2-1

What is the speed this motion?

• constant speed

• not moving

• speed increasing

• speed increasing at a constant rate

Answer explanation

The correct choice is 'constant speed' because it indicates that the motion does not change over time. The other options suggest variations in speed, which are not applicable here.

Tags

NGSS.MS-PS3-1

What happened during E to F point?

• not moving

• increasing speed at a constant rate

• moving at a 5 m/s

• moving at 5 m/s² acceleration

Answer explanation

During the E to F point, the object is moving at a constant speed of 5 m/s. This indicates that there is no acceleration or deceleration, confirming the correct choice.

Tags

NGSS.MS-PS3-1

NGSS.MS-PS3-5

which line represents the constant acceleration?

• A

• B and D

• C

• A, B, and D

Answer explanation

Lines A, B, and D represent constant acceleration as they show linear relationships in a velocity-time graph. Line C does not represent constant acceleration, as it may indicate varying acceleration.

Tags

NGSS.HS-PS2-1

What is the motion described in the graph 

• all of above

• constant speed

• constant acceleration

• constant position

Answer explanation

The graph indicates a change in velocity over time, which signifies constant acceleration. This means the object is speeding up or slowing down at a steady rate, making 'constant acceleration' the correct choice.

A ball is thrown upward in the air with an initial velocity of 40 m/s. How long does it take to reach back to the point it was thrown from?

• 4 seconds 

• 2 seconds 

• 6 seconds 

• 8 seconds 

Answer explanation

The time to reach the maximum height is given by t = v/g, where v = 40 m/s and g = 9.8 m/s². This gives t ≈ 4.08 seconds. The total time for the round trip is double this, approximately 8 seconds.

Tags

NGSS.HS-PS2-1

NGSS.HS-PS2-4