Differential Equations and Their Solutions

Differential Equations and Their Solutions

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

CCSS
HSF.BF.B.3, HSA.REI.B.3, HSA.REI.A.1

+1

Standards-aligned

Created by

Amelia Wright

FREE Resource

Standards-aligned

CCSS.HSF.BF.B.3
,
CCSS.HSA.REI.B.3
,
CCSS.HSA.REI.A.1
CCSS.HSF.BF.B.5
,
The video tutorial explains how to solve the differential equation Y' = KY, where K is a positive constant. Initially, a guessed solution is presented, but the video proceeds to solve the equation without guessing. It involves transforming the equation using calculus, finding the antiderivative, and solving for y using exponential equations. The tutorial concludes by confirming the general solution, y = c * e^(KX), incorporating the solution y = 0.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial guess for the solution to the differential equation Y' = KY?

y = c * e^(KX)

y = c * X^K

y = c * e^(-KX)

y = c * KX

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What assumption is made about y to rewrite the differential equation?

y = 0

y ≠ 0

y < 0

y > 0

Tags

CCSS.HSF.BF.B.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which theorem is used to switch the roles of X and Y in the equation?

Intermediate Value Theorem

Inverse Function Theorem

Mean Value Theorem

Fundamental Theorem of Calculus

Tags

CCSS.HSF.BF.B.3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the antiderivative of 1/y with respect to y?

y^2/2

e^y

1/y

ln|y|

Tags

CCSS.HSA.REI.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to both sides of the equation to solve for y?

Subtracting a constant

Taking the reciprocal

Taking the logarithm

Multiplying by a constant

Tags

CCSS.HSF.BF.B.5

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the logarithmic equation transformed into an exponential equation?

By multiplying by e

By raising e to the power of both sides

By dividing by e

By taking the square root

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution to the differential equation Y' = KY?

y = c * X^K

y = c * KX

y = c * e^(-KX)

y = c * e^(KX)

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