
Addition Method for Solving Systems

Interactive Video
•
Mathematics
•
8th - 10th Grade
•
Hard
Standards-aligned

Lucas Foster
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary goal of the addition method when solving systems of linear equations?
To graph the equations and find the intersection
To substitute values directly into the equations
To eliminate one variable by adding equations
To find the determinant of the matrix
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the first example, what happens to the Y terms when the equations are added?
They double in value
They become negative
They are eliminated
They remain unchanged
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving a system using the addition method?
Substitute values into the equations
Find the inverse of the matrix
Line up the variables vertically
Graph the equations
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the second example, why is it beneficial to eliminate the X terms instead of the Y terms?
It requires multiplying only one equation
It is the only possible method
It results in a simpler equation
It avoids negative coefficients
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of adding the equations in the second example after making the coefficients opposites?
A new equation with only Y terms
A new equation with only X terms
A new equation with both X and Y terms
A new equation with no variables
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the third example, what is the least common multiple used to eliminate the Y terms?
5
10
15
20
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the solution verified in the third example?
By using a calculator
By calculating the determinant
By checking the graph of the equations
By substituting the solution back into the original equations
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