Population Growth and Differential Equations

Population Growth and Differential Equations

Assessment

Interactive Video

Mathematics, Science

9th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains the unlimited growth model using a differential equation. It introduces the equation dydt = 0.1 * y and provides an initial condition y(0) = 350. The tutorial demonstrates a shortcut to solve this type of equation, leading to the general solution y(t) = C * e^(Kt). The example shows how to calculate the population size at time t = 5, resulting in approximately 577. The video concludes by mentioning alternative methods like separation of variables.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the differential equation dydt = 0.1 * y represent in the context of population growth?

A population with no change over time

A population growing at a rate proportional to its size

A population decreasing over time

A constant population size

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given in the problem?

y(0) = 100

y(0) = 500

y(0) = 0

y(0) = 350

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the goal of the problem regarding the population size?

To find the population size at time t = 0

To find the initial population size

To find the population size at time t = 5

To find the population size at time t = 10

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the shortcut method used for solving the differential equation?

Using the general solution y(t) = Ce^(Kt)

Separation of variables

Integration by parts

Differentiation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the general solution y(t) = Ce^(Kt), what does the constant C represent?

The time at which the population is measured

The final population size

The initial population size

The growth rate

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the constant K in the given problem?

0.2

0.1

0.05

0.5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the particular solution for the population size expressed?

y(t) = 350 * e^(0.5 * t)

y(t) = 350 * e^(0.2 * t)

y(t) = 350 * e^(0.1 * t)

y(t) = 350 * e^(0.05 * t)

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