Factorising polynomials

• (3x + 6)(3x + 2)

• (9x + 8)(x + 2)

Simplify the following using the square of a sum formula: (8 + z)^2

• 64 + 16z + z^2

• 8^2 + 2z + z^2

• 8^2 + z^2

• 64 - 16z + z^2

 $Expansion\ of\ \left(x\ +4\right)^2\ is\$  

•  $x^2+8x+16$  

• x $x^2+8x+4$  

•  $x^2-8x+16$  

•  $x^2+8x-16$  

pg. 17 #55b

• (x² + 20x + 440) in²

• (4x² + 42x + 440) in²

• (x² + 22x + 440) in²

• (4x² + 84x + 440) in²

Factor:  8x³ + 1

• (2x + 1)(4x² + 2x + 1)
• (2x + 1)(4x² - 2x + 1)
• (8x + 1)(x² + 1)
• (2x - 1)(4x² + 2x + 1)

The method we use to factor 4x² – 1 is called:

 $12x^2-27$  

•  $\left(4x^2-9\right)$  

•  $3\left(4x^2-9\right)$  

•  $\left(2x-3\right)\left(2x+3\right)$  

•  $3\left(2x-3\right)\left(2x+3\right)$  

Completely factor this polynomial $3x^2-24x+48$  

•  $3\left(x+4\right)^2$  

•  $3\left(x^2-8x+16\right)$  

•  $3\left(x+4\right)\left(x-4\right)$  

•  $3\left(x-4\right)^2$