Solving multi-step problems using quadratic equations in one variable

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CCSS.HSA-REI.B.4B

Solve using square roots
7x² + 6 = 13

• x = 1
• x = -7 & 7
• x = -1 & 1 
• x has no real solutions

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CCSS.HSA-REI.B.4B

• {625}

• {-625, 625}

• {-5, 5}

• {5}

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CCSS.HSA-REI.B.4B

• x= -7, x=3

• x=7, x=3

• x=7, x=-3

• none of the above

Tags

CCSS.HSA-REI.B.4B

Solve using square root method: (x+9)² - 1 = 10

• (-6,0) (-12,0)

• (9,0) (10,0)

• (-5.68,0) (-12.32,0)

• no solution

Tags

CCSS.HSA-REI.B.4B

Pick which equation I can use square roots to solve:

• 3x² + 2x + 1 = 0

• 3x² -27 = 0

• 3x² + 2x = 1

• 4x + 10 = 0

Tags

CCSS.HSA-REI.B.4B

Which method should be used to solve the quadratic function? Explain.

4x² - 16 = 0

• Square Roots; there is no "bx" term.

• The Quadratic Formula; it cannot be solved using another method.

• Factoring; it is factorable using a GCF.

Tags

CCSS.HSA-REI.B.4B

Solve by square rooting:

5b² - 4 = 41

• b = 9, b = -9

• b = 3, b = -3

• b = 8, b = -8

• no solution

Tags

CCSS.HSA-REI.B.4B

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CCSS.HSA-REI.B.4B

What method of solving equations should you use for this equation?

 $2x^2+5=0$  

• factoring

• use square roots

• both methods work

• neither method works

Tags

CCSS.HSA-REI.B.4B